Answer:
1. The combined number of protons and neutrons remains constant.
2. There are two atoms with mass numbers of 2.
3. It is the number of protons plus neutrons.
4. A nucleus with a greater mass than any of the reactants will be produced.
5. Fusion reactions in the sun convert small amounts of matter into large amounts of energy.
Answer:
The work done by the system is 100 J
Explanation:
Given details
The cross sectional area of the of the container is A = 100.0 cm^2 = 0.01m²
The total distance pushed by the piston is d = 10 cm = 0.10m
The total external pressure by which piston pushed is P = 100 kPa
From above data, the following relation can be used to determine the change in volume of the container
∆V = A * d
∆V = 0.01 * 0.10 = 0.001 m³
By using the following relation, the work done by the system is calculated as;
Work done W = P * ∆V
W = 100 * 0.001 = 0.1 kJ = 100 J
The work done by the system is 100 J
Answer:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Explanation:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Methane + oxygen → carbon dioxide + Water.
The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.
The mole ratio of combustion are as follows:
1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.
