<u>Answer</u>:
The coefficient of static friction between the tires and the road is 1.987
<u>Explanation</u>:
<u>Given</u>:
Radius of the track, r = 516 m
Tangential Acceleration
= 3.89 m/s^2
Speed,v = 32.8 m/s
<u>To Find:</u>
The coefficient of static friction between the tires and the road = ?
<u>Solution</u>:
The radial Acceleration is given by,




Now the total acceleration is
=>
=>
=>
=>
The frictional force on the car will be f = ma------------(1)
And the force due to gravity is W = mg--------------------(2)
Now the coefficient of static friction is

From (1) and (2)


Substituting the values, we get


The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 *
m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 ×
C
mass of electron = 9.1 ×
kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 ×
* 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m * 
= 1/2 * 9.1 ×
* 
equation both the equations
1/2 * 9.1 ×
*
= 1.6 ×
= 0.352 *
m/s
= 35.2 * 
= 5.93 *
m/s
To learn more about kinetic energy in electric field here
brainly.com/question/8666051
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Answer:
t = 12s
Explanation:
Given:
v-initial = 0 m/s
x = 360 m
a = 5.0 m/s^2
Solve:
x = (v-initial)t + 1/2(a*t^2)
360 = 0t + 1/2 (5.0t^2)
360 = 2.5 t^2
144 = t^2
t = sqrt(144) = 12
Therefore, it takes 12 seconds.
Power is the work done per unit time. Therefore,

Therefore,
Answer:
150153.06122 N
Explanation:
m = Mass of person = 75 kg
h = Height of fall = 1 m
g = Acceleration due to gravity = 9.81 m/s²
F = Force
s = Displacement = 0.49 cm
Potential energy is given by

Work is given by

The average force exerted is 150153.06122 N