Ask question

Ask question

All categories

3 years ago

5

Write an expression for the potential energy UD of a particle when it is at a distance D from the force center, in terms of B an

d D, where B is the constant of proportionality. Assume the potential energy to be zero when the particle is at infinity.

1 answer:

nadezda [96]3 years ago

7 0

Answer:

E+mc+UD-3

Explanation:

You might be interested in

The specific heat of water is 4,186 J/kg.'C. Approximately how much heat must

Artyom0805 [142]

Explanation:

Q= mc∆T

∆T= 5-24=- 19

Q= 0.5*4186*-19

Q= -39767 J

negative sign show heat releases

4 0

2 years ago

PLEASEEEEEE HEEEEEEEEEEEEEEELPPPPPPPPPPPPPPPPP I NED HELP WHIT THIS!!!!! D:

aleksley [76]

The meters per second
+1t a second / 2t

6 0

2 years ago

A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a

hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

$a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2$

So the magnitude of the total acceleration is

$a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2$

4 0

3 years ago

1. What distance is required for a train to stop if its initial velocity is 23 m/s and its

Irina-Kira [14]

Answer:

x=?

dt=?

vi=23m/s

vf=0m/s (it stops)

d=0.25m/s^2

time =

vf=vi+d: 0=23m/s+(0.25m/s^2)t

t=92s

displacement=

vf^2=vi^2+2a(dx)

23^2=0^2+2(0.25m/s^2)x =-1058m

Explanation:

you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m

6 0

3 years ago

Consider again the civilization described in the previous question. (They live on a planet orbiting 10 AU from a close binary st

Veseljchak [2.6K]

Fysbsts dydbdysj dudgts offhand fidydh jdgdhd

6 0

2 years ago