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bekas [8.4K]
3 years ago
7

Whats the answer lol

Chemistry
1 answer:
Sveta_85 [38]3 years ago
6 0
At first I thought it was c but then I checked And it’s either B or A? I’m thinking mostly A but good luck
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Calculate the amount of heat required to raise the temperature of an 64 g sample of water from 32 ∘C to 69 ∘C.
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Answer:

9945.6 J

Explanation:

Amount of heat = Mass * Heat Capacity * Temperature Change

Heat capacity of Water = 4.2 J/gC

Amount of heat = 64 * 4.2 * (69 - 32)

Amount of heat = 64 * 4.2 * 37

Amount of heat = 9945.6 J

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Which of the following statements is true about the metric system ?
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Koi mera aake chus lo Aur heela bhi do​
Svet_ta [14]

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7 0
4 years ago
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Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C
Leno4ka [110]

Explanation:

The reaction equation will be as follows.

    C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)

Using bond energies, expression for calculating the value of \Delta H is as follows.

    \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

On reactant side, from C_{2}H_{6} number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From Cl_{2}; Cl-Cl bonds = 1

On product side, from C_{2}H_{5}Cl number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

  \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

  =[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]            = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0
3 years ago
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