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ruslelena [56]
3 years ago
10

13. When a train car traveling at 4 m/s collides with a stationary train car, what happens to the momentum of the first train ca

r?
Chemistry
1 answer:
Solnce55 [7]3 years ago
5 0

Answer:

Momentum of first train car will reduce

Explanation:

When the moving care collides with the stationary car, it will increase the momentum of the stationary car. However, its own momentum will reduce.

It is so because the speed of the first train car will reduce after collision due to loss of energy in the collision while the stationary car may gain some momentum due to rise in velocity from zero (velocity at stationary position).

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2 The substance has a mass of 0.50 kg.
katen-ka-za [31]

Answer:

68000J/kg

Explanation:

Given parameters:

 Mass of the substance  = 0.5kg

 Quantity of heat transferred to the body  = 34000J

 

Unknown:

Specific latent heat of fusion = ?

Solution:

The specific latent heat is usually involve in phase changes;

  H  = mL

H is the quantity of heat supplied

m is the mass

L is the specific latent heat

 Insert the parameters and solve;

     34000 = 0.5 x L

         L  = \frac{34000}{0.5}   = 68000J/kg

5 0
3 years ago
23492u undergoes alpha decay. what is the atomic number of the resulting element.
mash [69]
Alpha decay involves the loss of an alpha particle, aka a helium nucleus. This results in the mass number of the original element decreasing by 4 and the atomic number decreasing by 2. Assuming 23942u is uranium (92), the resulting element's atomic number is 90, making it thorium.
4 0
3 years ago
An electrochemical cell is constructed using electrodes with the following half-cell reactions.
marshall27 [118]

Answer:

E cell = +1.95 V

Explanation:

At Anode : Oxidation reaction takes place

At Cathode : Reduction reaction takes place

The reaction with lower value of reduction potential will undergo Oxidation

Mn^{2+}(aq)+2e^{-}\rightarrow Mn(s)   E = -1.18 V

This equation undergo oxidation reaction and become:

Anode(Oxidation-Half) :

Mn(s)\rightarrow Mn^{2+}(aq)+2e^{-}      E = +1.18 V

Cathode(Reduction-Half) :

Fe^{3+}(aq)+e^{-}\rightarrow Fe^{2+}    E =+0.77 V

To balance the reaction multiply reduction-Half with 2.We get :

Fe^{3+} +2Mn(s)+\rightarrow Fe^{2+} + 2Mn^{2+}

Note that E is intensive property , do not multiply E  of oxidation-half with 2

Ecell =  0.77 -(-1.18)

E = +1.95 V

3 0
3 years ago
What is the chemical law?
NeTakaya

Answer:

Chemical laws are those laws of nature relevant to chemistry. The most fundamental concept in chemistry is the law of conservation of mass, which states that there is no detectable change in the quantity of matter during an ordinary chemical reaction. Modern physics shows that it is actually energy that is conserved, and that energy and mass are related; a concept which becomes important in nuclear chemistry. Conservation of energy leads to the important concepts of equilibrium, thermodynamics, and kinetics.

Explanation:

Have A Wonderful Day !!

8 0
3 years ago
Read 2 more answers
I NEED THIS IN 5 MIN PLS FAST What is the difference between a physical and chemical property?
Kamila [148]

Answer:

physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change

7 0
4 years ago
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