Answer:
The answer to the question is 2.2khz
Explanation:
<em>Let z₁ = 5.4m</em>
<em>Let z₂ = 4.6m</em>
<em>The path difference Δz = z₁-z₂ = 5.4 - 4.6 = 0.8m</em>
<em>For the interference= Δz λ, 2λ, 3λ......</em>
<em>The wavelength λ = 0.8m</em>
<em>The speed of sound v = 344m/s</em>
<em>The frequency f = v/λ = 344/0.8 = 430hz</em>
<em>Now,</em>
<em>f₁ =f, f₂= 2f, f₃ = 3f, f₄= 4f, f₅ =5f which is,</em>
<em>f₁ =f = 430Hz, f₂=2f =860Hz, f₃ =3f =1290Hz f₄ =4f =1720Hz and f₅=5f =2150Hz</em>
<em>f5 = 2120Hz = 2.200Hz </em>
<em>we will convert to two significant figures =2.2kHz</em>
<em> </em>
