Answer:
Explanation:
Given data:
initial construction co = 0.286 wt %
concentration at surface position cs = 0 wt %
carbon concentration cx = 0.215 wt%
time = 7 hr
![D = 7.5 \times 10^{-11} m^2/s](https://tex.z-dn.net/?f=D%20%3D%20%207.5%20%5Ctimes%2010%5E%7B-11%7D%20m%5E2%2Fs)
for 0.225% carbon concentration following formula is used
![\frac{cx -co}{cs -co} = 1 - erf(\frac{x}{2\sqrt{DT}})](https://tex.z-dn.net/?f=%5Cfrac%7Bcx%20-co%7D%7Bcs%20-co%7D%20%3D%201%20-%20erf%28%5Cfrac%7Bx%7D%7B2%5Csqrt%7BDT%7D%7D%29)
where, erf stand for error function
![\frac{cx -co}{cs -co} = \frac{0.215 -0.286}{0 -0.286} =0.248](https://tex.z-dn.net/?f=%5Cfrac%7Bcx%20-co%7D%7Bcs%20-co%7D%20%3D%20%5Cfrac%7B0.215%20-0.286%7D%7B0%20-0.286%7D%20%3D0.248)
![0.248 = 1 - erf(\frac{x}{2\sqrt{DT}})](https://tex.z-dn.net/?f=0.248%20%3D%201%20-%20erf%28%5Cfrac%7Bx%7D%7B2%5Csqrt%7BDT%7D%7D%29)
![erf(\frac{x}{2\sqrt{DT}}) = 1 - 0.248](https://tex.z-dn.net/?f=erf%28%5Cfrac%7Bx%7D%7B2%5Csqrt%7BDT%7D%7D%29%20%3D%201%20-%200.248)
![erf(\frac{x}{2\sqrt{DT}}) = 0.751](https://tex.z-dn.net/?f=erf%28%5Cfrac%7Bx%7D%7B2%5Csqrt%7BDT%7D%7D%29%20%3D%200.751)
from the table erf(Z) value = 0.751 lie between (z) = 0.80 and z = 0.85 so by inteerpolation we have z = 0.815
from given table
![\frac{x}{2\sqrt{DT}} = 0.815](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%5Csqrt%7BDT%7D%7D%20%3D%200.815)
![x = 2\times 0.815 \times \sqrt{7.5 \times 10^{-11}\times (7\times 3600)](https://tex.z-dn.net/?f=x%20%3D%202%5Ctimes%200.815%20%5Ctimes%20%5Csqrt%7B7.5%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20%287%5Ctimes%203600%29)
![x = 2.39\times 10^{-3} m](https://tex.z-dn.net/?f=x%20%3D%202.39%5Ctimes%2010%5E%7B-3%7D%20m)
x = 0.002395 mm
Answer:
Program that removes all spaces from the given input
Explanation:
// An efficient Java program to remove all spaces
// from a string
class GFG
{
// Function to remove all spaces
// from a given string
static int removeSpaces(char []str)
{
// To keep track of non-space character count
int count = 0;
// Traverse the given string.
// If current character
// is not space, then place
// it at index 'count++'
for (int i = 0; i<str.length; i++)
if (str[i] != ' ')
str[count++] = str[i]; // here count is
// incremented
return count;
}
// Driver code
public static void main(String[] args)
{
char str[] = "g eeks for ge eeks ".toCharArray();
int i = removeSpaces(str);
System.out.println(String.valueOf(str).subSequence(0, i));
}
}
Answer:
A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:
Answer:
True
Explanation:
The CNC is the primary interface between the machine operator and the machine.