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pochemuha
3 years ago
13

Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic

(i.e., single-wavelength) EM radiation on a metal plate with unknown work function W, and then measuring the stop- ping voltage required to bring the ejected electrons to a halt. When he uses λ1= 400 nm, he finds that a stopping voltage of V1 = 0.7 V is required. When he uses λ2 = 500 nm, he finds that a stopping voltage of V2= 0.2 V is required. Based on these two data points, what is Ajani's measurement of Planck's constant?
Physics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

h = 1.01 x 10⁻³⁴ J.s

Explanation:

The energy applied by the voltage must be equal to the energy associated with the wavelength of light:

eV = \frac{hc}{\lambda}\\

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = stopping potential

h = Planck's Constant = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light

For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:

(1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\

h = 1.49 x 10⁻³⁴ J.s

For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:

(1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\

h = 0.53 x 10⁻³⁴ J.s

Taking average of both values:

h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}

<u>h = 1.01 x 10⁻³⁴ J.s</u>

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