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2 years ago

2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the

Chemistry

1 answer:

solmaris [256]2 years ago

3 0

Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball = 10kg

Height of the rail = 20m

Unknown:

Velocity at the bottom of the rail = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

V² = U² + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

the ball was rolled from rest, U = 0

V² = O² + 2 x 9.8 x 20

V = 19.8m/s

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4. A balloon is filled with 3.0 L of helium at 310 K. The balloon is placed in an oven where the

77julia77 [94]

Answer:

3,29L

Explanation:

3.29L = V2

Formula: V1/T1 = V2/T2

--------------------

Given:

V1 = 3.0 L V2 = ?

T1 = 310 K T2 = 340 K

--------------------

Plugin:

(X stands in place of V2 just to make it easier to look at)

[3.0L / 310K = X / 340K]

(3.0L / 310K = 0.01L/K)

0.01L/K = X / 340K

(multiply 340K on both sides, it cancels out on the right)

0.01L/K * 340K = X

(0.01L/K * 340K = 3.29L)

**3.29L = X**

[or]

**3.29L = V2**

4 0

2 years ago

Deuterium is a relatively uncommon form of hydrogen, but can be created from what common source?.

Elena-2011 [213]

Deuterium is a relatively uncommon form of hydrogen, but can be created from water.

Heavy hydrogen commonly known as deuterium
stable isotopes of hydrogen
gets its name from the Greek word deuterons means second.
has only one proton and one neutron
nucleus of the hydrogen's deuterium atom is known as a deuteron containing one proton and one neutron.
Deuterium forms chemical bonds that are stronger than regular hydrogen
gas deuterium is colorless
Deuterated water is used in Magnetic Resonance Spectroscopy.
used in the determination of the isotopologue of various organic compounds.
used in Infrared Spectroscopy.

To know more about Deuterium visit : brainly.com/question/27870183

#SPJ4

8 0

1 year ago

Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What

coldgirl [10]

Answer:

$\rm_{90}^{231}\text{Th}$

Explanation:

The unbalanced nuclear equation is

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + X$

Let's write X as a nuclear symbol.

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} + _{Z}^{A}\text{X}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

92 = 2 + Z , so Z = 92 - 2 = 90

And your nuclear equation becomes

$\rm _{92}^{235}\text{U} \longrightarrow \, _{2}^{4}\text{He} +\, _{90}^{231}\text{X}$

Element 90 is thorium, so

$\rm X = _{90}^{231}\text{Th}$

7 0

3 years ago

A chemist must prepare of sodium hydroxide solution with a pH of at . He will do this in three steps: Fill a volumetric flask ab

77julia77 [94]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

By definition, $pH = -log[H_3O^+]$ .
NaOH is a strong base, as it's a hydroxide formed with a group 1A metal, so it dissociates fully in water by the equation: $NaOH (aq)\rightarrow Na^+ (aq) + OH^- (aq)$ .
From the equation above, using stoichiometry we can tell that the molarity of hydroxide is equal to the molarity of NaOH: $[NaOH] = [OH^-]$ .
Concentration of hydroxide is then equal to the ratio of moles of NaOH and the volume of the given solution. Moles themselves are equal to mass over molar mass, so we obtain: $[OH^-] = [NaOH] = \frac{n_{NaOH}}{V} = \frac{m_{NaOH}}{M_{NaOH}V}$ .
We also know that $pOH = 14.00 - pH = -log[NaOH]$ . Take the antilog of both sides: $10^{-pOH} = 10^{pH - 14.00} = [NaOH] = \frac{m_{NaOH}}{M_{NaOH}V}$ .
Solve for the mass of NaOH: $m_{NaOH} = 10^{pH - 14.00}\cdot M_{NaOH}\cdot V$ .

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

$m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g$

7 0

2 years ago

Why are there 2 chloride ions for every 1 calcium in calcium chloride

tensa zangetsu [6.8K]

Answer:

See explanation

Explanation:

Calcium is divalent. This means that it donates two electrons during ionic bond formation. Since chlorine atom can only accept one electron during ionic bond formation, two chlorine atoms must accept the two electrons donated by calcium.

For this purpose, each time CaCl2 is formed, there must be two chlorine atoms for each calcium atom.

5 0

3 years ago