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vazorg [7]
3 years ago
6

2. A 10 kg ball is rolled down a rail from a height of 20 m. What is the velocity at the bottom of the

Chemistry
1 answer:
solmaris [256]3 years ago
3 0

Answer:

19.8m/s

Explanation:

Given parameters:

Mass of the ball  = 10kg

Height of the rail  = 20m

Unknown:

Velocity at the bottom of the rail  = ?

Solution:

The velocity at the bottom of the rail is its final velocity.

Using the appropriate motion equation, we can find this parameter;

   V²   = U²  + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

  the ball was rolled from rest, U  = 0

  V²  = O²  + 2 x 9.8 x 20

 V  = 19.8m/s

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How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut
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4.94g of material

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Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

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100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

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<em>Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.</em>

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