Answer:
Ryobi P517 18V Lithium Ion Cordless Brushless 2,900 SPM Reciprocating Saw w/ Anti-Vibration Handle and Tool-Less Blade Changing
Explanation:
Answer:
c. 0.033T - 2.6 °C
Explanation:
Hello,
In this case, we should conclude that the energy lost by the water is gained by the ice to get melted, thus, we can write them in terms of melting and cooling enthalpies:
First term includes melting enthalpy of ice that is 333.89 J/g and the second one specific heat of water that is 4.18 J/g°C, therefore, we obtain:
Thus, answer should be c. 0.033T - 2.6 °C since it includes the temperature decrease of water due to the undergoing cooling.
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Answer:
Difference between Homogeneous mixture and Heterogeneous Mixture are as follows:
- A mixture or sample that is consist of uniform composition and properties is called a homogeneous mixture while a mixture or sample that is consist of different composition and properties is called a heterogeneous mixture.
- Homogenous mixture has only single phase while heterogeneous mixture has two or more phases.
- Homogenous mixture can not be separated by physical methods while heterogeneous mixture can be separated out physically.
- Example of homogenous mixture is Water and sugar and heterogeneous mixture is oil and water.
Answer:
True.
Explanation:
hydrogen and oxygen=water or hydrogen oxide
H+O2=H2O.
The total pressure in the container is <u>2.02</u> atm.
<em>Step</em> 1. Calculate the<em> total number of moles.
</em>
Moles of He = 1.00 g He × (1.00 mol He/4.003 g He) = 0.2498 mol He
Moles of F₂ = 14.0 g F₂ × (1 mol F₂/38.00 g F₂) = 0.3684 mol F₂
Moles of Ar = 19.00 g Ar × (1 mol Ar/39.95 g Ar) = 0.4756 mol Ar
<em>Total moles</em> = (0.2498 + 0.3684 + 0.4756) mol = <em>1.094 mol
</em>
<em>Step </em>2. Calculate the <em>total pressure</em>.
Use the <em>Ideal Gas Law</em>: <em>pV = nRT
</em>
We can solve the equation to get the pressure:
<em>p</em> = (<em>nRT</em>)/<em>V</em>
<em>n</em> = 1.094 mol
<em>R</em> = 0.082 06 L·atm·K⁻¹mol⁻¹
<em>T</em> = (20.0 + 273.15) K = 293.15 K
<em>V</em> = 13.0 L
∴ <em>p</em> = (1.094 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 293.15 K)/13.0 L = 2.02 atm