All categories

3 years ago

Which are functions of proteins?

Physics

2 answers:

NikAS [45]3 years ago

5 0

D. to be structural material

sweet-ann [11.9K]3 years ago

4 0

The answer is d to be a structural material

You might be interested in

What valves in this diagram need to be opened to allow liquid to flow?

-BARSIC- [3]

I'd guess at valve B. more information about the interesting question would help.

5 0

3 years ago

A machine part has the shape of a solid uniform sphere of mass 205 g and diameter 4.10 cm. It is spinning about a frictionless a

kondor19780726 [428]

Answer:

Answer is in the following attachment.

Explanation:

3 0

3 years ago

A particle travels clockwise on a circular path of diameter R, monitored by a sensor on the circle at point P; the other endpo

kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

$sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}$

With this function we should only calculate the derivate in function of c

$\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}$

That is the rate of change of $\theta$ .

b) At this point we need only make a substitution of 0 for c in the equation previously found.

$\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}$

Hence we have finally the rate of change when c=0.

6 0

3 years ago

Figure 3 shows a bicycle of mass 15 kg resting in a vertical position, with the front and back

Vinil7 [7]

Explanation:

There are three forces on the bicycle:

Reaction force Rp pushing up at P,

Reaction force Rq pushing up at Q,

Weight force mg pulling down at O.

There are four equations you can write: sum of the forces in the y direction, sum of the moments at P, sum of the moments at Q, and sum of the moments at O.

Sum of the forces in the y direction:

Rp + Rq − (15)(9.8) = 0

Rp + Rq − 147 = 0

Sum of the moments at P:

(15)(9.8)(0.30) − Rq(1) = 0

44.1 − Rq = 0

Sum of the moments at Q:

Rp(1) − (15)(9.8)(0.70) = 0

Rp − 102.9 = 0

Sum of the moments at O:

Rp(0.30) − Rq(0.70) = 0

0.3 Rp − 0.7 Rq = 0

Any combination of these equations will work.

3 0

3 years ago

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

zysi [14]

Given that,

Mass of each washer = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer $m= 4.9\times10^{-3}\ Kg$

So, Mass of two washers is

$M=2\times m$

Put the value of m

$M=2\times4.9\times10^{-3}\ k$

$M=0.0098\ Kg$

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

$F=mg$

Put the value into the formula

$F=4\times4.9\times10^{-3}\times9.8$

$F=0.192\ N$

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

6 0

3 years ago