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matrenka [14]
3 years ago
11

Which of the following is a FALSE statement? *

Chemistry
1 answer:
-Dominant- [34]3 years ago
8 0

Answer:

C: Warm water is denser than cold water

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oee [108]
A physical change. When a physical change occurs the chemical composition of the substance doesn't change. Some examples of physical changes are melting, freezing, vaporization, and condensation.
5 0
3 years ago
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The rate law for the rearrangement of ch3nc to ch3cn at 800 k is rate = (1300 s-1)[ch3nc]. what is the half-life for this reacti
Lana71 [14]
The rate of reaction is always expressed in concentration per time like mol/L·s. The equation is:

r [mol/L·s] = kCⁿ, where n is the order of reaction. Since k is 1300/s, that means that Cⁿ = C such that (1/s)*(mol/L) = mol/L·s. Thus, n=1. For a first order reaction, the formula would be:

ln(A/A₀) = -kt
where
A is the amount of material after time t
A₀ is the amount of material at t=0

The half life is when A/A₀ = 1/2÷1 = 1/2. Thus, the half-life t is:

ln(1/2) = (-1300t)
t = 5.33×10⁻⁴ seconds
3 0
3 years ago
A hydrocarbon has the molar mass 26.04 g/mol. what is a possible formula
jonny [76]
C2H2 is the right answer I believe
6 0
3 years ago
How many moles of Fe2O3 are in 17.2g?<br><br> A - 1.23<br> B - 2.75<br> C - 0.239<br> D - 0.108
Firdavs [7]

Answer:

C

Explanation:

8 0
3 years ago
Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.
Makovka662 [10]

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

  • experience a change in its temperature, which involves sensible heat,
  • undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

  • Q: amount of heat
  • m: mass
  • L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

  • Q: amount of sensible heat  
  • m: body mass
  • c: specific heat of the substance
  • ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is  4.184 \frac{J}{g*C}:

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 \frac{J}{g*C})* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 \frac{J}{g}:

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 \frac{J}{g}) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is  2.02 \frac{J}{g*C} :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 \frac{J}{g*C})*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

<u><em>The total amount of energy required is 25,515.2 J.</em></u>

5 0
3 years ago
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