If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases from 20.5°C to 47.8 °C.

A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams

kakasveta [241]

Answer:

A. 3.2grams

Explanation:

First we need to get the chemical equation for this reaction:

CO + H₂ → CH₃OH

We then need to balance the equation:

CO + 2H₂ → CH₃OH

Our next step is to first convert our given into moles. We do this by figuring out first how many grams of each substance there are in 1 mole by adding up the atomic mass of each element in each substance.

Carbon(1) Oxygen(1)

CO = 12.011(1) + 15.999(1) = 28.01 g/mole

Hydrogen(2)

H₂ = 1.008(2) = 2.016g/mole

We can then use this to determine how many moles of each reactant we have given the mass.

$CO = 2.8g\\2.8g\times\dfrac{1mole}{28.01g}=0.1moles\\\\H_{2}=0.50g\\\\0.50g\times\dfrac{1mole}{2.016g}=0.469moles$

So here we have our new given:

0.1 moles of CO

0.496 moles of H₂

We then need to determine how much product we produce with our given.

According to our chemical equation we can assume that:

For every 1 mole of CO we can produce 1 mole of CH₃OH

Fore every 2 moles of H₂ we can produce 1 mole of CH₃OH

Using this ratio we can determine how much product each reactant will produce by using the ratios:

$0.1 moles of CO\times\dfrac{1moleofCH_{3}OH}{1moleofCO}=0.1moles of CH_{3}OH\\\\ 0.496molesofH_{2}\times\dfrac{1moleofCH_{3}OH}{2molesofH_{2}}=0.248molesofCH_{3}OH$

Now notice that they are not equal. The reactant that produces the least amount of product will be our limiting reactant. The limiting reactant determines the amount of product that is produced, because once it is completely used up, the reaction stops. So in this case, the amount of CH₃OH that is produced is 0.10 moles.

Now we need to figure out how many this is in grams. To do that we need to find out how many grams of CH₃OH there are in 1 mole of CH₃OH.

Carbon (1) Hydrogen(4) Oxygen(1)

CH₃OH = 12.001(1) + 1.008(4) + 15.999(1)

= 12.001 + 4.032 + 15.999 = 32.032g/mole

We then use this for converting:

$0.10 moles\times\dfrac{32.032g}{1mole}=3.2032g$

So the reaction will produce 3.2032g of CH₃OH or 3.2g of CH₃OH

3 0

3 years ago

In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol

zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

Step 1: Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

Step 2: The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

Step 3: mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0

3 years ago

The amount of chemical weathering will increase if

olga2289 [7]

Chemical Weathering is the process of decomposition, erosion and spoilage of Solid materials like Building Material, Rocks e.t.c.
This decomposition takes place due to chemical reaction. The chemical present in Air along with water undergo chemical decomposition of Solid materials.
So, first requirement for this process is water, which is present in air called precipitation. Secondly, temperature also play important role.

Result:
The amount of chemical weathering will increase if Temperature and Precipitation Increases.

8 0

3 years ago

The energy due to motion of molecules within a mass is called

andrezito [222]

Answer:

Heat.

Explanation:

6 0

3 years ago

Concerning the 10.0 mL of 0.50 M NaCl diluted to 100 mL of solution:

balu736 [363]

No because If you put 10 g of salt in a 1 L of water and then add another 9 L of pure water, there is still 10 g of salt but it's now dissolved in 10 L of water, not 1.

3 0

3 years ago

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