Bb, or mostly dominant with a little recessive
Answer:
63.01284 g/mol
Explanation:
This compound is also known as Nitric Acid.
Convert grams HNO3 to moles or moles HNO3 to grams
Molecular weight calculation:
1.00794 + 14.0067 + 15.9994*3
Percent composition by element
Element Symbol Atomic Mass # of Atoms Mass Percent
Hydrogen H 1.00794 1 1.600%
Nitrogen N 14.0067 1 22.228%
Oxygen O 15.9994 3 76.172%
Chadwick, Thompson, Rutherford, Bohr
<span>First, the child's weight must be converted from pounds to kilograms.
1 lb is equal to 0.453592 kg, so a 13 lb child weighs:
13 lb * 0.453592 kg/lb = 5.896696 kg
Next, use the child's converted weight to determine the mg dosage. The recommended dose is 15 mg per kg, so the recommended dose is:
15 mg/kg * 5.896696 kg = 88.45044 mg
Finally, determine how many mL are needed to provide the calculated mg dosage. One unit of the suspension is 80 mg/0.80 mL. In order to provide 88.45044 mg, you will need
88.45044 mg / 80 mg = 1.1056305 units of the suspension.
Multiplying this by the 0.80 mL portion of the unit of the suspension, you get the final mL dosage:
0.80 mL * 1.1056305 = 0.8845044 mL
A 13 lb child should receive 0.8845044 mL of the 80mg/.8mL suspension.</span>
15.9 grams is the amount of copper sulfate this reaction will produce.
Given:
- The reaction between copper and sulfur:
- 12.7 grams of copper completely reacts with 3.2 grams of sulfur to give copper sulfide.
To find:
The mass of copper sulfide produced
Solution
Mass of copper used by the scientist = 12.7 g
Mass of sulfur used by the scientist = 3.2 g
Mass of copper sulfide this reaction will produce. =?
According to the law of conservation of mass:
Total mass of reactants = Total mass of products
The total mass of reactants in the reaction = R = 12.7 g + 3.2 g = 15.9 g
The total mass of product formed in the reaction = P
P = R = 15.9 g
Mass of copper sulfide this reaction will produce = 15.9 g
15.9 grams is the amount of copper sulfate this reaction will produce.
Learn more about the law of conservation of mass:
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