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SSSSS [86.1K]
3 years ago
12

If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases from 20.5°C to 47.8 °C.

Chemistry
1 answer:
kozerog [31]3 years ago
7 0

Explanation:

Have a good luck with ur exam

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otez555 [7]
The answer is D, use Pythagorean theorem.
4 0
3 years ago
19. When 0.5g of calcium trioxocarbonate (IV) was added to excess dilute
Flauer [41]

Answer:

0.1gmin-1

Explanation:

mass = 0.5g

time = 5minutes

rate= mass/time = 0.1gmin-1

7 0
3 years ago
A solution of H2SO4(aq) with a molal concentration of 5.25 m has a density of 1.266 g/mL. What is the molar concentration of thi
Igoryamba
<span>There are a number of ways to express concentration of a solution. This includes molarity and molality. Molarity is expressed as the number of moles of solute per volume of the solution.  MOlality is expressed as moles per kg solution. 

5.25 mol H2SO4 / kg solution ( 1 kg / 1000 g ) ( 1.266 g / mL ) ( 1000 mL / 1L ) = 6.6 M H2SO4</span>
5 0
3 years ago
What is the pH of 0.26 M ammonium ion? NH4+(aq) + H2O(1) NH3(aq) + H30* (aq) a. 4.33 b.9.25 c. 3.87 d. 4.92 e. 4.75
choli [55]

Answer:

b) pH = 9.25

Explanation:

  • NH4+(aq)  +  H2O(l)  ↔  NH3(aq)  +  H3O+(aq)
  • NH3 + H2O ↔ NH4+  +  OH-
  • 2 H2O ↔ H3O+  +  OH-

⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature

mass balance NH4+:

⇒ M NH4+ = [ NH4+ ] - [ OH- ]

∴ [ NH3 ] ≅ M NH4+ = 0.26 M

⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5

⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6

⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0

⇒ [ OH- ] = 1.859 E-5 M

⇒ pOH = - Log ( 1.859 E-5 )

⇒ pOH = 4.7305

⇒ pH = 14 - pOH = 9.269

6 0
3 years ago
PLEASE HELP ASAP I need help with this
dangina [55]

Answer:

sorry pic wont work

Explanation:

i can help if you get the pic to work

4 0
3 years ago
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