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Juliette [100K]
3 years ago
8

2) An electron cloud

Chemistry
1 answer:
Hunter-Best [27]3 years ago
6 0

Explanation:

d because black bla black bla

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5. How many grams of potassium bromide will dissolve in 450g of water at 80°C?
Shtirlitz [24]
Hi mate. I think the answer is 100
6 0
3 years ago
The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear
djverab [1.8K]

Answer: The rate of appearance of Br_2 is 0.0700Ms^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = -\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2 = \frac{1d[H_2]}{dt}

Rate in terms of appearance of Br_2 = \frac{1d[Br_2]}{dt}

-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}

Given :

-\frac{1d[HBr]}{dt}=0.140Ms^{-1}

The rate of appearance of Br_2;

\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}

Thus rate of appearance of Br_2 is 0.0700Ms^{-1}

6 0
3 years ago
Indique cuáles son las unidades de la molaridad * <br> eq-g/m³ <br> eq-g/L <br> mol/cm³ <br> mol/L
Westkost [7]

Answer:

hm

Explanation:

3 0
3 years ago
0.274 is equal to what in mL?
Murrr4er [49]
274ml's that is if you are converting from Liters
4 0
4 years ago
What is the molarity of a solution made by mixing 75.0 mL of 3.00 M NH₄OH with enough water to give 250. mL of solution?
enyata [817]

Answer:

Mass 1=3M

Mass 2=?

Volume1=75mL

Volume2=250mL

By using molarity formula:

<u>mass1*volume 1=mass2*volume 2</u>

3M*75=mass2*250

mass2=225/250

mass2:0.9M

<h3>the molarity of a solution is 0.9M.</h3>
7 0
3 years ago
Read 2 more answers
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