Answer:
Smog can be classified as two types. They are
Oxidizing smog
Reducing smog
Oxidizing smog:
The smog which has the property of high concentration of oxidizing agents is known as oxidizing smog. Oxidizing smog can also known as photochemical smog.
Example: Ozone.
Reducing smog:
The smog which has high concentration of sulfur Dioxide is known as reducing smog.Photochemical smog which is very dangerous is called oxidizing smog because it consists of the oxidizing agent ozone.......the other one is reducing smog which consists of reducing agent sulphurdioxide.
Answer:
197 + (35.5×3) = 303.5
Explanation:
relative formula mass is the sum of the relative atomic masses of the atoms in the formula ( AuCl3 )
It's adenosine triphosphate !
it has Penrose sugar and phosphate as backbone !
and nitrogenous base ... adenine.... in the middle !
Answer:
0.0611M of HNO3
Explanation:
<em>The concentration of the NaOH solution must be 0.1198M</em>
<em />
The reaction of NaOH with HNO3 is:
NaOH + HNO3 → NaNO3 + H2O
<em>1 mole of NaOH reacts per mole of HNO3.</em>
That means the moles of NaOH used in the titration are equal to moles of HNO3.
<em>Moles HNO3:</em>
12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.
In 25.00mL = 0.025L -The volume of the aliquot-:
0.00153 moles HNO3 / 0.025L =
<h3> 0.0611M of HNO3</h3>
