Answer:
kinetic energy will change by a factor of 1/2
Option C) 1/2 is the correct answer
Explanation:
Given the data in the question;
we know that;
Kinetic energy = 1/2.mv²
given that mass of the object is doubled; m1 = 2m
speed is halved; v1 = V/2
Now, New kinetic energy will be; 1/2.m1v1²
we substitute
Kinetic Energy = 1/2 × 2m × (v/2)²
Kinetic Energy = 1/2 × 2m × (v²/4)
Kinetic Energy = 1/2 × m × (v²/2)
Kinetic Energy = 1/2 [ 1/2mv² ]
Kinetic Energy = 1/2 [ KE ]
Therefore; kinetic energy will change by a factor of 1/2
Option C) 1/2 is the correct answer
Answer:
11.64225 m
Explanation:A = 45 m/s – 15m/s / 6s
A = 5m/s^2
Answer:
η = 0.667 = 66.7%
Explanation:
The efficiency of the man can be given by the following formula:
η = output/input
where,
η = efficiency of man = ?
output = potential energy gain of the box = Wh
input = work done by man = Fd
Therefore,
where,
W = weight of box = 200 N
h = height gained by box = 1 m
F = force exerted by man = 60 N
d = length of ramp = 5 m
Therefore,
<u>η = 0.667 = 66.7%</u>
Answer: Hello mate!
lets define the north as the y-axis and east as the x-axis.
Using the notation (x,y) we can define the initial position of the car as (0,0)
then the car travells 13 mi east, so now the position is (13,0)
then the car travels Y miles to the north, so the position now is (13, Y)
and we know that the final position is 25° degrees north of east of the initial position. This angle says that the distance traveled to the north is less than 13 mi because this angle is closer to the x-axis (or east in this case).
This angle is measured from east to north, then the adjacent cathetus is on the x-axis, in this case, 13mi
And we want to find the distance Y, so we can use the tangent:
Tan(25°) = Y/13
tan(25°)*13 mi = Y = 6.06 mi.
