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kotegsom [21]
3 years ago
9

If you deposit ₱10,000 into an account that earns 5% annual interest compounded semiannually, how long will it take until there

is ₱12,000 in the bank account
Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

t = 3.69 ≈ 3. 7 years

Step-by-step explanation:

Given :

P = 10,000

r = 5%= 0.05

A = 12,000

n = 2 ( because it is compounded semi - annually )

 

  A = P (1 + \frac{r}{n})^{nt}\\

12000 = 10000(1 + \frac{0.05}{2})^{2 t}\\\\1.2 = ( 1 + \frac{0.05}{2})^{2t}\\\\1.2 = (1.025)^{2t}\\\\log \ 1.2 = 2t \ log \ 1.025\\\\2t = \frac{log 1.2 }{log 1.025} \\\\2t = \frac{0.1823}{0.0247}\\\\2t = 7.3805\\\\t = 3.69

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2(x-1)-y=-8 <br> y=2x+8 <br> substitution method
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Answer:

No Solution.

Step-by-step explanation:

2(x-1)-y=-8

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3 years ago
The length and breadth of rectangular room is 10 cm and 5 cm. Find the area of perimeter​
julsineya [31]

Answer:

P= 30 cm

Step-by-step explanation:

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3 0
2 years ago
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Step-by-step explanation:

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Answer:

The first, third, and fourth answer choices represent a function.

Step-by-step explanation:

A relation is a relationship between sets of values. The two quantities that are being related to each other are the input (x-variable) and the output (y-variable). But relations in general aren't always a good way to relate between x and y.

Say that I have situation where I want to give <em>x </em>dollars to the cashier so he can change them to <em>y</em> quarters. Here is a "example" of the relation:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       2       |          12

Do you see something wrong here? Yes! We all know that you can't exchange 2 dollars for 12 quarters. You can only exchange 2 dollars for 8 quarters and only 8 quarters. This is a general reason why we don't rely on general relations for real-life situations. One x-variable does not exactly map to one and only one y-variable.

However, a relation that can map one x-variable to one and only one y-variable is known as a function. Let's make the above example an actual function to prove a point:

Dollars (x) | Quarters (y)            

----------------------------------              

       0       |          0                      

        1       |          4                      

       2       |          8

       3       |          12

Now, the 3 dollars make 12 quarters as it should. This is how a function should look like.

There are two ways to check if a relation is a function. On a relation, table, or a set of ordered pairs, you have to make sure there is no "x-variable" that repeats. All x-values of a relation have to be unique in order to be a function. On a graph, you can also perform the Vertical Line Test. If you draw vertical lines over a relation and if the lines cross only once, then it is a function. If not, it fails the Vertical Line Test.

So to answer you're question, the first, third, and fourth choices are functions because they all have unique x-variables. The second choice is not a function because it fails the Vertical Line Test.

7 0
2 years ago
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