The molarity of a solution is 0.909 M.
m(CaCl₂) = 82 g; mass of calcium chloride
M(CaCl₂) = 111 g/mol; molar mass of calcium chloride
n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)
n(CaCl₂) = 82 g ÷ 111 g/mol
n(CaCl₂) = 0.74 mol; amount of calcium chloride
V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride
c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)
c(CaCl₂) = 0.74 mol ÷ 0.812 L
c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride
Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.
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Answer: The molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.
Explanation:
Given:
= 43.6 mL,
= 0.125 M
= 25.0 mL,
= ?
Formula used to calculate the concentration of acid is as follows.
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Substitute the values into above formula.

Thus, we can conclude that the molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.
The given elements put into an equation using their symbols are as follows:
Pb +
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=
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+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +
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=
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+ Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
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=
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+ Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +
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=
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+ 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Answer:
I think it's more than 100,000 mold
There are no above options to choose from so I am giving an example of a X3Y2 formula which is Magnesium nitride, the formula is Mg3N2.