Question

A skateboarder is moving at 2.00m/s and increases his velcity at a rate of 1.6m/s/s for 6.0 seconds. What is the displacement of the skateboarder during this game? Must include Given, Find , and Equation. Show all work .

Answer 1

Answer:

S = 40.8m

Explanation:

Given the following data;

Initial velocity, u = 2m/s

Acceleration, a = 1.6m/s²

Time, t = 6secs

Required to find the displacement

Displacement, S = ?

The displacement of an object is given by the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Where;

• S represents the displacement measured in meters.

• u represents the initial velocity measured in meters per seconds.

• t represents the time measured in seconds.

• a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$S = 2*6 + \frac {1}{2}*(1.6)*6^{2}$

$S = 12 + 0.8*36$

$S = 12 + 28.8$

S = 40.8m

Therefore, the displacement of the skateboarder during this game is 40.8 meters.