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2 years ago

identify the reagents necessary to achieve each of the following transformations o3 dms, pcc, ch2cl, h2so4,h2o,hgso4

Chemistry

1 answer:

hoa [83]2 years ago

3 0

the reagents necessary to convert alcohol to ketone $Na_2Cr_2O_7 , H_2O$ which involves oxidation of alcohols.

<h3>What is oxidation of alcohols?</h3>

Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
In order to cause primary alcohols to oxidize into aldehydes

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern

oxidation of secondary alcohols to ketones

$Cr_2O_7 ^-^2$ (dichromate)
$CrO_3$ /pyridine (Collins reagent)
Chromium pyridinium compound (PCC)
Dichromate of pyridinium (PDC, Cornforth reagent)
Periodinane by Dess-Martin
Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
$CrO_3, H_2SO_4$ /acetone (Jones oxidation)
Acetone with aluminum isopropoxide (Oppenauer oxidation)

To learn more about oxidation of alcohols with the given link

brainly.com/question/7207863

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Question:

Identify the reagents necessary to achieve each of the following transformations

$a. O_3 , DMS$

$b.H_2SO_4 , H_2O , HgSO_4$

$c.Na_2Cr_2O_7 , H_2O$

$d.Fe ^ {2+}, NaOH$

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lana66690 [7]

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2 years ago

Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1

NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x x x

The dissociation constant from the above reactions is given by:

$Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}$

$6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}$

$6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0$

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

$pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75$

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

$\% = \frac{x}{[HCN]} \times 100$

$\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100$

$\% = 3.5 \cdot 10^{-3} \%$

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!

6 0

2 years ago

If the freezing point of an aqueous 0.10 m glucose solution is −x°c, what is the approximate freezing point of a 0.10 m nacl sol

maks197457 [2]

Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
Van't Hoff factor (i) for NaCl solution is approximately 2.
Van't Hoff factor (i) for glucose solution is 1.
Change in freezing point from pure solvent to solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per kilogram of solvent.
Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.

8 0

3 years ago

A sample of Ca(OH)2 is considered to be an Arrhenius base because it dissolves in water to yield

postnew [5]

The answer is C. Arrhenius bases increase the concentration of OH- in solution.

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3 years ago

Read 2 more answers

A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon

ikadub [295]

Answer: The enthalpy of the reaction is 269.4 kJ/mol

Explanation: