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Softa [21]
3 years ago
7

Covalent solutes are considered non-electrolytes. What does this mean for the conductivity of the solution? A) Non-electrolytes

dissolve and completely dissociate in water providing charged ions to conduct electricity. B) Non-electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity. C) Being a non-electrolyte refers the type of bonding and has no bearing on conducting electricity. D) Non-electrolytes do not dissolve in water and can not conduct electricity.
Chemistry
2 answers:
Serggg [28]3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

When a chemical compound dissociates into ions in a solution then the resulting solution is known as electrolyte.

For example, HCl dissolved in water will act as an electrolyte.

And, when a chemical compound does not dissociate into ions when dissolved in a solvent then the resulting solution is known as a non-electrolyte.

For example, CCl_{4} in water will act as a non-electrolyte.

As a non-electrolyte does not contains ions therefore, they do not conduct electricity. Also, covalent compounds do not dissociate into ions when dissolved in water.

Thus, we can conclude that the statement non-electrolytes do not dissolve in water and can not conduct electricity, is true.

iogann1982 [59]3 years ago
5 0

Electrolytes are those which dissociates in solution and produces ions.

Ions can carry current,so Electrolytes conduct electiricity.

And non electrolytes are those which do not dissociate in solution and doesnt produce ions.

Since non electrolytes do not produce ions they cannot conduct electricity.

<u>Hence the right option is:</u>

B) Non-electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.  

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Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

8 0
3 years ago
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