Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.
<h3>Definition of ideal gas</h3>
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
<h3>Ideal gas law</h3>
An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
<h3>Volume of gas</h3>
In this case, you know:
- P= 1.50 atm
- V= ?
- n= 500 g×
= 11.36 moles, being 44
the molar mass of CO₂ - R= 0.082

- T= 25 C= 298 K (being 0 C=273 K)
Replacing in the ideal gas law:
1.50 atm×V = 11.36 moles×0.082
× 298 K
Solving:
V= (11.36 moles×0.082
× 298 K) ÷ 1.50 atm
<u><em>V= 184.899 L</em></u>
Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.
Learn more about the ideal gas law:
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vitamins is the answer to your question
Right now it's written in scientific notation, so you can just move the decimal place in 3.8 to the right 3 times (as it is times 10 to the third power) to get 3,800g.
Answer:
The yearly release of
into the atmosphere is
.
Explanation:

Annual production of CaO = 
Moles of CaO :

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with
of CaO moles of carbon-dioxide moles produced will be:
of carbon-dioxide
Mass of
moles of carbon-dioxide:

The yearly release of
into the atmosphere is
.