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3 years ago

Help please and please

Engineering

1 answer:

nataly862011 [7]3 years ago

8 0

So people can tell what your think

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8.17 Water is the working fluid in a Rankine cycle. Superheated vapor enters the turbine at 10 MPa, 4808C, and the condenser pre

katrin2010 [14]

Answer:

attached below

Explanation:

8 0

3 years ago

Can somebody help me with that

skelet666 [1.2K]

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

4 0

3 years ago

A platform and a weight totaling 900 N is held in position by a vertical water jet of 5 cm diameter. Determine the velocity of t

BlackZzzverrR [31]

Answer:

v = 21.409 m/s

Explanation:

Given data:

Total weight of the platform and weight together, W = 900 N

Diameter of the water jet = 5 cm = 0.05 m

Now,

the force exerted by the water jet is balancing the platform

also,

Force exerted by the water jet = ρAv²

where,

ρ is the density of the water = 1000 kg/m³

A is the area of the outlet of the jet = $\frac{\pi}{4}d^2=\frac{\pi}{4}(0.05)^2$

A = 0.00196 m²

v is the velocity of the jet

thus,

W = ρAv²

900 = 1000 × 0.00196 × v²

v = 21.409 m/s

Hence, the velocity of the jet is 21.409 m/s

7 0

3 years ago

There are four functions of a hydraulic fluid. Which of the following is not a function? a. preventing fires d. none of the abov

kiruha [24]

Answer:

Out of the options given

option (a) preventing fires

is not a function of hydraulic fluid.

Explanation:

Hydraulic fluid is the medium for energy tranfer in all hydraulic sytems. Simple functioning of hydraulic fluid can be easily gained by using a fluid that does not trap gasses easily.

To transmit energy is the basic and the core function of any hydraulic fluid. Apart from this function, there are four other basic functions:

1) to transfer heat

2) to remove contaminant

3) to provide sealing

4) for lubrication

7 0

3 years ago

Cos square there + cos square theta multiply cot square theta = cot square theta

Ivahew [28]

Explanation:

We need to prove that : $\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta$

Taking LHS : $\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta$

Taking $\cos^2\theta$ common as follows :

$\cos^2\theta(1+ \cot^2\theta)$ ...(1)

We know that :

$cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta$ ....(2)

Use equation (2) in equation (1) as follows :

$\cos^2\theta{\cdot} cosec^2\theta$

We know that : $cosec\theta=\dfrac{1}{\sin\theta}$

So,

$\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta$

=RHS

Hence, LHS = RHS

8 0

3 years ago