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Virty [35]
3 years ago
7

What are the building blocks of starch molecules​

Chemistry
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

Glucose is the building block for starch

Explanation:

(amylose and amylopectin)

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olga nikolaevna [1]

Answer:

Heat or electricity in the atmasphere

Explanation:

4 0
2 years ago
A kicked soccer ball<br> eventually comes<br> to rest. What<br> force causes<br> this?<br> ce
maks197457 [2]

Answer:

friction

Explanation:

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7 0
3 years ago
At STP, 2.24 L of carbon dioxide gas is collected. What is the number of molecules of gas present in this volume?
Doss [256]

Considering the definition of STP conditions and Avogadro's number, the number of molecules of gas present in 2.24 L is 6.023×10²² molecules.

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Definition of Avogadro's number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of molecules of carbon dioxide gas</h3>

At STP, 2.24 L of carbon dioxide gas is collected. So, you can apply the following rule of three: if by definition of STP conditions 22.4 L are occupied by 1 mole of carbon dioxide gas, 2.24 L are occupied by how many moles of carbon dioxide gas?

amount of moles of carbon dioxide gas=\frac{2.24 Lx1 mole}{22.4 L}

amount of moles of carbon dioxide gas= 0.1 moles

Finally, 0.1 moles of carbon dioxide gas are collected.

Then you can apply the following rule of three, considering the Avogadro's number:  If 1 mole of carbon dioxide gas contains 6.023×10²³  molecules, 0.1 mole of carbon dioxide gas contains how many molecules?

amount of molecules of carbon dioxide gas= (6.023×10²³ molecules × 0.1 moles)÷1 mole

amount of molecules of carbon dioxide gas=6.023×10²² molecules

Finally, the number of molecules of gas present in 2.24 L is 6.023×10²² molecules.

Learn more about

STP conditions:

brainly.com/question/26364483

brainly.com/question/8846039

brainly.com/question/1186356

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ1

8 0
2 years ago
8.38e-21 Q^2 -1.07e-23 Q^2 +3.15e+19<br> Solve for Q
GarryVolchara [31]
8.38e -21Q^2 -1.07e -23Q^2 +3.15e +19
= 10.46e -44Q^2 + 19
44Q^2 = 10.46e + 19
Q^2 = 523/2200e + 19/44
Q1= ≈ -1.03828
Q2= ≈ 1.03828
4 0
3 years ago
Convert 771.8 g to kg
Molodets [167]
The amount of kilograms is 0.7718
8 0
3 years ago
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