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Basile [38]
2 years ago
9

In a water molecule (H2O), the oxygen atom has two unshared pairs of electrons and two bonding pairs of electrons. How do the un

shared pairs affect the bond angle?
Chemistry
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

They reduce the bond angle to be slightly lower than the tetrahedral bond angle, approximately 104.45 degrees.

Explanation:

The unshared pair of electrons or lone pair electrons in order to have the minimum repulsion possible with each other pushes the other bonding pairs closer together making the bond angle smaller or bent.

The bond angle is slightly lower than the tetrahedral bond angle of 108 degrees, leaving the water molecule with a bent molecular geometry.

You might be interested in
Which of the following is an example of a decomposition reaction?
Flura [38]

Answer:

A simple example of decomposition reaction is hydrolysis of water where a water molecule is broken down into hydrogen and oxygen gas.

8 0
2 years ago
Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the
daser333 [38]

Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

  • Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.
  • Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.

From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

  • Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.
  • Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.
  • Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position
  • Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.
  • Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

4 0
3 years ago
Methane and water react to form hydrogen and carbon monoxide, like this:
Usimov [2.4K]

Based on Le Chatelier's principle, if a system at equilibrium is disturbed by changes in the temperature, pressure or concentration, then the equilibrium will shift in a direction to undo the effect of the induced change.

The given reaction is endothermic i.e, heat is supplied:

CH4(g) + H2O (g) + heat ↔ 3H2(g) + CO(g)

a) When the temperature is lowered, heat is being removed from the system. The reaction will move in a direction to produce more heat i.e. to the left.

Hence, the pressure of CH4 will increase and equilibrium will shift to the left

b) When the temperature is raised, heat is being added to the system. The reaction will move in a direction to consume the added heat i.e. to the right.

Hence, the pressure of CO will increase and equilibrium will shift to the right

7 0
3 years ago
Please heeelp to solve these problems​
Darya [45]

Answer:

Q.89

Alkane - CnH(2n+2)

given that 8 H = > 8= 2n+2

therefore n= 3

C3H8 = 12×3 + 8×1= 36 +8 = 44

4 0
3 years ago
The graph shows the solubility of several different salts in water, across a range of temperatures. According to the
sladkih [1.3K]

Answer:

  • <u><em>Sodium chloride</em></u>
  • See the graph attached

Explanation:

The attached graph with a green and a red arrow facilitates the understanding of this explanation.

To read the <em>solubility </em>on the <em>graph</em>, you can start with the temperature, on the x-axis.

The red vertical arrow shows how, departing from the <em>40ºC temperature</em> on the x-axis, you intersect the<em> solutibility curve </em>of sodium chloride at a height (y-axis) corresponding to <em>60 g/100cm³ of water</em> (follow the green horizontal arrow).

Hence, <em>sodium chloride is the salt that can dissolve at a concentration of about 60g/100cm³ of water at 40ºC.</em>

4 0
3 years ago
Read 2 more answers
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