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frutty [35]
3 years ago
9

Write the formulas of the compounds formed by Pb4+ with the following anions: NO3−, HCO3−, SO32−, PO43−. Use the given order of

anions?

Chemistry
2 answers:
vredina [299]3 years ago
8 0
Pb(NO₃)₄
Pb(HCO₃)₄
Pb(SO₃)₂
Pb₃(PO₄)₄
Sloan [31]3 years ago
8 0

<u>Answer:</u> Four ionic compounds formed will be Pb(NO_3)_4,Pb(HCO_3)_4,Pb(SO_3)_2\text{ and }Pb_3(PO_4)_4

<u>Explanation:</u>

Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.

We are given:

One cation having formulas Pb^{4+}

Four anions having formulas NO_3^-,HCO_3^-,SO_3^{2-}\text{ and }PO_4^{3-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

The four ionic compounds are:

When lead ion and nitrate ions combine, it results in the formation of Pb(NO_3)_4 compound. This is named as lead (IV) nitrate.

When lead ion and bicarbonate ions combine, it results in the formation of Pb(HCO_3)_4 compound. This is named as lead (IV) hydrogen carbonate.

When lead ion and sulfite ions combine, it results in the formation of Pb(SO_3)_2 compound. This is named as lead (IV) sulfite.

When lead ion and phosphate ions combine, it results in the formation of Pb_3(PO_4)_4 compound. This is named as lead (IV) phosphate.

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