Question

Write the formulas of the compounds formed by Pb4+ with the following anions: NO3−, HCO3−, SO32−, PO43−. Use the given order of anions?

Answer 1

Pb(NO₃)₄
Pb(HCO₃)₄
Pb(SO₃)₂
Pb₃(PO₄)₄

Answer 2

Answer: Four ionic compounds formed will be $Pb(NO_3)_4,Pb(HCO_3)_4,Pb(SO_3)_2\text{ and }Pb_3(PO_4)_4$

Explanation:

Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.

We are given:

One cation having formulas $Pb^{4+}$

Four anions having formulas $NO_3^-,HCO_3^-,SO_3^{2-}\text{ and }PO_4^{3-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

The four ionic compounds are:

When lead ion and nitrate ions combine, it results in the formation of $Pb(NO_3)_4$ compound. This is named as lead (IV) nitrate.

When lead ion and bicarbonate ions combine, it results in the formation of $Pb(HCO_3)_4$ compound. This is named as lead (IV) hydrogen carbonate.

When lead ion and sulfite ions combine, it results in the formation of $Pb(SO_3)_2$ compound. This is named as lead (IV) sulfite.

When lead ion and phosphate ions combine, it results in the formation of $Pb_3(PO_4)_4$ compound. This is named as lead (IV) phosphate.