here's the solution,
work done (w) = force (f) × displacement (s)
=》
![w = 1200 \times 5](https://tex.z-dn.net/?f=w%20%3D%201200%20%5Ctimes%205)
=》
![6000](https://tex.z-dn.net/?f=6000)
workdone = 6000 joules,
now, we know
power (p) = workdone ÷ time taken
=》
![p = \frac{6000}{3}](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B6000%7D%7B3%7D%20)
=》
![p = 2000 \: watts](https://tex.z-dn.net/?f=p%20%3D%202000%20%5C%3A%20watts)
Answer:
Direction of wave traveling is +X direction.
Explanation:
Given :
Direction of electric field =
direction
Direction of magnetic field =
direction
We know that electromagnetic waves is transverse wave.
The direction of electric field and magnetic field are perpendicular to each other.
So we write,
![\vec E \times \vec B = \vec n](https://tex.z-dn.net/?f=%5Cvec%20E%20%5Ctimes%20%5Cvec%20B%20%3D%20%5Cvec%20n)
Where
direction of propagation.
Put the direction on above equation,
![-\vec k \times \vec j = \vec n](https://tex.z-dn.net/?f=-%5Cvec%20k%20%5Ctimes%20%5Cvec%20j%20%3D%20%5Cvec%20n)
From the right hand rule we can say that direction of wave propagation is +X direction.
The distance from the sun to Neptune is about the same as the distance from Neptune to the next closest star, Proxima Centauri
<span>(A)
s{ t } = (¼)t² + 2t + 1 ... differentiate to get velocity versus time
v{ t } = (½)t + 2 ... linearly increases with time
(1)
Vavɢ{ a→b } = [ v{ b } + v{ a } ] ⁄ 2
Vavɢ{ 1→3 } = [ v{ 3 } + v{1 } ] ⁄ 2
Vavɢ{ 1→3 } = [ (½)(3) + 2 + (½)(1) + 2 ] ⁄ 2
Vavɢ{ 1→3 } = 3 m/sec
(II) and (III) are done the same way.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...
(B)
v{ t } = (½)t + 2
v{1 } = (½)(1) + 2
v{1 } = 2.5 m/sec</span>