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cluponka [151]
3 years ago
7

A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa & absorbs energy of 84 J. Calculate the change i

n internal energy?
Physics
1 answer:
leonid [27]3 years ago
4 0

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

1W2 = P1 (V2 – V1)

= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ

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. A 5 kg turkey and a 3.5 kg turkey are suspended on opposite sides of a single pulley.
zavuch27 [327]

Answer:

a) 40.3725 N

b) a=1.729 m/s^2

Explanation:

mass of turkey 1 M= 5 kg

mass of turkey 2 m= 3.5 kg

Let T be the tension in the string and a be the acceleration of the system

then from FBD in the attachment

T-mg=ma.................1

Mg-T=Ma..................2

from 1 and 2 we find a as

a= \frac{Mg-mg}{M+m}

now substituting the values we get

a= \frac{5g-3.5g}{5+3.5}

a= \frac{1.5g}{8.5}

a=1.729 m/s^2

now from equation 1 we can calculate Tension T as

T-mg=ma

T= m(a+g)

T= 3.5(1.729+9.81)= 40.3725 N

6 0
3 years ago
A 3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 4 + 15.7 x − 1.5 x 2 , where Fx
garik1379 [7]

Answer:

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = \int\limits^b_a {Fx} \, dx.................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

<em>Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²</em>

Substituting these values into equation 1

<em>W = \int\limits^a_b {(4 + 15.7x - 1.5x^{2} )dx} \,</em>

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

Work = 28.44 J

Work done by the force = 28.44 J.

8 0
3 years ago
Using a simple machine, a student is able to lift a 500N weight by applying only 100N.
pishuonlain [190]
Hey there!

a \ student  \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only  \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\   \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer!

Hope this helps you!
7 0
3 years ago
What is the mechanical advantage of a single pulley
Viktor [21]

the answer is 1 because a single pulley has 1 rope


5 0
4 years ago
Read 2 more answers
What energy output objects work with the turbine
Angelina_Jolie [31]

Answer:

maybe alternator..generator..

4 0
3 years ago
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