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Rainbow [258]
2 years ago
5

Which of the following is a product formed when Ag2O decomposes

Chemistry
1 answer:
Eva8 [605]2 years ago
6 0
The decomposition of Ag2O can be illustrated using the following equation:
<span>2Ag2O .............> 4Ag + O<span>2

From the above balanced reaction, you can see that the decomposition of Ag2O produces O2 which is oxygen gas and Ag which is silver precipitate.</span></span>
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Tectonic plates make up which of the following layers of the Earth?
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The lithosphere makes up the layer of the earth.
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Identify and describe the different forms of precipitation shown in the images.
Nutka1998 [239]

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It was first just snow but now its snow ball eggs that's what it looks like hope it helps:)

Explanation:

4 0
2 years ago
Find the mass of 5.60 mol NaOH
olga_2 [115]
The mass is 224 grams of NaOH
7 0
2 years ago
A 13 Ohm resistor, R, is connected to a battery with unknown voltage, V, as shown below. The total current, I, flowing through t
wlad13 [49]

Answer:

16.12 V

Explanation:

Ohms law explains or portrays the relationship between the voltage (V), current (I) and resistance (R). This is represented using the equation as follows:

V = IR

Where;

V = voltage (Volts)

I = current (amperes)

R = resistance (ohms)

According to the information provided in the question, resistance (R) = 13 Ohm, current (I) = 1.24 Amperes, V = ?

V = 13 × 1.24

V = 16.12 V

3 0
2 years ago
At a given temperature, K = 1.3x10^-2 for the reaction:
son4ous [18]

Answer:

a) 0.11

b)76.9

c) 8.8

d) 1.7*10^-4

Explanation:

Step 1: Data given

K = 1.3 * 10^-2 for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g)

Step 2: Formula of K

aA(g) + bB(g) ⇌ cC(g) + dD(g)

K = [C]^c *[D]^d  / [A]^a * [B]^b

K = 1.3 * 10^-2 = [NH3]² / [H2]³*[N2]

Step 3:

a) 1/2N2 + 3/2H2(g) ⇌ NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

1/2N2 + 3/2H2(g) ⇌ NH3(g)    =>K' =  \sqrt{K}

K' = \sqrt{1.3*10^-2} = 0.11

<em>b. 2NH3(g) ⇌ N2(g) + 3H2(g)</em>

N2(g) + 3H2(g) ⇌ 2NH3

2NH3(g) ⇌ N2(g) + 3H2(g)    =>K' = 1/K

K' = 1/(1.3*10^-2) = 76.9

c. NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)

N2(g) + 3H2(g) ⇌ 2NH3

NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)    

=>K' = \frac{1}{\sqrt{K} }

K' = \frac{1}{\sqrt{1.3*10^-2} }

K' = 8.8

d. 2N2(g) + 6H2(g) ⇌ 4NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

2N2(g) + 6H2(g) ⇌ 4NH3(g)

K' = K²

K' = (1.3*10^-2)²

K' = 1.7 *10 ^-4

4 0
2 years ago
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