As more bulbs are added in parallel, the current strength will decrease OR. As more bulbs are added in parallel, the current strength will increase.
Answer:
Option D.
Explanation:
From the question given above, the following data were obtained:
Force applied (F) = 5 N
Extention (e) = 0.075 m
Spring constant (K) =?
The spring constant for the spring can be obtained as follow:
F = Ke
5 = K × 0.075
Divide both side by 0.075
K = 5 / 0.075
K = 67 N/m
Thus, the spring constant for the spring is 67 N/m
Answer:
10.5 m/s
Explanation:
For the first chestnut:
y₀ = 10 m
v₀ = 0 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
y = 10 + (0) t + ½ (-9.8) t²
y = 10 − 4.9t²
When y = 7.5:
7.5 = 10 − 4.9t²
t = 5/7
When y = 0:
0 = 10 − 4.9t²
t = 10/7
For the second chestnut:
y₀ = 10 m
y = 0 m
a = -9.8 m/s²
t = 10/7 s − 5/7 s = 5/7 s
y = y₀ + v₀ t + ½ at²
0 = 10 + v₀ (5/7) + ½ (-9.8) (5/7)²
0 = 10 + 5/7 v₀ − 2.5
v₀ = -10.5
The second chestnut must be thrown downwards at 10.5 m/s.
Looks like a double covalent bond.