A bullet is at rest. It travels a distance of 0.34m in a time of 0.0095 seconds. Calculate its acceleration

A constant magnetic field of 0.50 T is applied to a rectangular loop of area 3.0 × 10-3 m2. If the area of this loop changes fro

Nonamiya [84]

Answer:

e= 0.440 mV(millivolt)

Explanation:

Given Magnetic field B= 0.50T

$A_{1}=3\times10^{-3}$

$A_{2}=1.6\times10^{-3}\\$

Δt= 1.6sec

$induced emf e=\frac{\mathrm{d} \phi }{\mathrm{d} t}$

⇒ $e=B\frac{\mathrm{d} A}{\mathrm{d} t}$

$e=0.50\times\frac{3\times10^{-3}-1.6\times10^{-3}}{1.6}$

$e=0.440\times10^{-3} volt$

e= 0.440 mV(millivolt)

8 0

3 years ago

What is the primary way that metamorphic rocks forms?

Sladkaya [172]

Answer:

where the rocks are exposed to really hot conditions and high pressure....these conditions are found deep where tectonic plates meet or deep inisde the earth past our core

hope this helps !!!!!

5 0

3 years ago

Read 2 more answers

I have a set of calipers that can measure thickness of a few inches with an uncertainty of ±0.005 inches. I measure the thicknes

Shtirlitz [24]

Answer:

(a) 0.0113 ±0.0001 inches

(b) 5 decks

Explanation:

<u>Given information</u>

52 cards, thickness is 0.590 ±0.005 inches

Since this is thickness of all the cards, to get the thickness of a single card we divide the total thickness (plus uncertainty) by the number of cards hence

1 card= $\frac {0.590}{52}$ ± $\frac {0.005}{52}$ = 0.0113461 ±0.000096 inches

Considering that thickness is given to 3 significant figures while uncertainty is to 1 significant figure, the final answer should also conform to these hence giving the first part of the answer to 3 significant figures while second part to 1 significant figure yields 0.0113 ±0.0001 inches

(b)

Considering that the cards have uncertainty of 0.0001 inches and the number of decks, n required to create uncertainty of 0.00002 inch is given by

$n=\frac {0.0001}{0.00002}=5$

We need 5 decks for the given uncertainty

4 0

3 years ago

A car accelerates at a constant rate from 12 m/s to 27 m/s while it travels 125 m. How long does it take to achieve this speed?

MArishka [77]

Answer:

6.41 s

Explanation:

Under constant acceleration we know that

average velocity × time taken = displacement

$s=\frac{u+v}{2}t$

$125=\frac{27+12}{2}t$

t = 6.41 s

The proof of used equation is given in the attachment.

3 0

3 years ago

A car starts from rest and accelerates uniformly over a time of 7.25 seconds for a distance of 210 m. Determine the acceleration

lara31 [8.8K]

Answer:

Acceleration is 7.990487515m/s²

Initial velocity is 0m.s

Explanation:

s=ut+(1/2)at²

210=0(7.25)+(1/2)a(7.25²)

210=26.28125a

∴a=7.990487515m/s²

'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.

8 0

3 years ago