What does this graph represent? A. speed B. velocity C. acceleration D. momentum?
1 answer:
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3.08 is the pOH of a 0.175 M aqueous solution of .
0.215% is the per cent ionization of a 0.325 M aqueous solution of
pH is a measure of how acidic/basic water is.
A)
→
Kb = 4.5 x
Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).
concentration of (NH₄⁺) = concentration of (OH⁻) = x.
x² = Kb x concentration of (NH₃)
x² = 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.
x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)
= 8.367 × 10⁻⁴
pOH = -log(c(OH⁻))
=- log ( 8.367 × 10⁻⁴)
= 3.08
B)
Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.
Concentration of (NX₃) = 0.325 M.
Kb = 4.5 x 10⁻⁶.
[NX₃H⁺] = [OH⁻] = x.
[NX₃] = 0.325 M - x.
Kb = [NX₃H⁺] x [OH⁻] ÷ [NX₃].
4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).
x = 0.0007 M.
Per cent of ionization:
α = 0. 0007 M ÷ 0. 325 M x 100%
= 0.215%.
Hence,
3.08 is the pOH of a 0.175 M aqueous solution of .
0.215% is the per cent ionization of a 0.325 M aqueous solution of
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Answer:
2-methylebutane
Explanation:
it is a hydrocarbon and there is a specific Rule for its nomenclature.
that is known as IUPAC naming system. According to it
- The compound that has all single bonds name ends on ane.
- Names according to the number of Carbons,
* For one carbon compound it is known as methane,
* For 2 ethane,
* For 3 propane
* For 4 Butane and so on.
- select the longest chain of compound
- Start numbering with lowest substituted position at carbon
- branch compound name as Iso and neo as whole
So keeping in mind the compound can be named as
2-methylebutane
- As the longest chain contain four carbon atoms so it will name as butane
- The substitution of methyl group is on C-2
*Note: it can also named as isopantane as it is branched and have five carbons but it could not be 3-isopentane.
