Answer:
0.1
Explanation:
We must first put down the equation of the reaction in order to guide our solution of the question.
2HNO3(aq) + Sr(OH)2(aq) -------> Sr(NO3)2(aq) + 2H2O(l)
Now from the question, the following were given;
Concentration of acid CA= ??????
Concentration of base CB= 0.299M
Volume of acid VA= 17.8ml
Volume of base VB= 24.7ml
Number of moles of acid NA= 2
Number of moles of base NB= 1
From;
CAVA/CBVB= NA/NB
CAVANB= CBVBNA
CA= CBVBNA/VANB
SUBSTITUTING VALUES;
CA= 0.299 × 24.7 ×2 / 17.8×1
CA= 0.8298 M
But;
pH= -log[H^+]
[H^+] = 0.8298 M
pH= -log[0.8298 M]
pH= 0.1
Answer:
Technical program - cosmetologist
Answer:
5.625 grams
Explanation:
Start your equation with what you have been given. Place the units you need in your answer on the right side of the equal sign.
225mg
----------- X ----------- X ------------- = ? g
lb
Now start to fill in your equation and use a conversions to get rid of the units you don't want. Convert mg into grams first. The child's weight (25 lb) is placed over 1 just to get the equation lined up properly so you can see how the units cancel out.
225 mg 1 g 25 lb 5.625 g
--------------- X --------------- X ------------- = ---------------
lb 1000 mg 1 1
The lb on the top and bottom cancel each other out and you are left with just grams. Even though it is over one, that is the same at just 5.625 grams.
They are more likely to be covalent as covalent compounds usually tend to be radical on the color spectrum with deep purples and blacks and even earwax colored.
Answer:
![\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctext%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
Explanation:
At the beginning, you have two reactions happening:
As you add KOH(aq), it does two things:
- It increases the volume of the solution.
- It reacts with the hydronium ions to form water.
A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.
B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.
C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.
D) As HClO₂ reacts, it forms ClO₂⁻. ![\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctextbf%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
