Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
Alkali metals<span> include </span>lithium<span>, sodium, potassium, rubidium, cesium and francium. These </span>metals<span> have large atomic radii and generally lose electrons during reactions. They have relatively soft textures, which makes them easy to mold, shape and dissect for </span><span>various uses</span>
Answer:
C
cell wall only in plants
chloroplast only in plants
enlarged vacuoles only in plants
cell membrane in both
hope this helps :)
Explanation:
Answer:
argon has no tendency to gain nor lose electrons.
Explanation: it's a noble gas
<span>1. Make an Observation. Scientists are naturally curious about the world. ...
2. Form a Question. After making an interesting observation, a scientific mind itches to find out more about it. ...
3. Form a Hypothesis. ...
4. Conduct an Experiment. ...
<span>5. Analyse the Data and Draw a Conclusion.</span></span>
