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frez [133]
2 years ago
14

________ are molecules whose general structure includes a central carbon with a carboxyl group, an amine group, a hydrogen molec

ule, and a residual (r) group.

Chemistry
1 answer:
IgorLugansk [536]2 years ago
5 0

The amino acids are the molecules where we can found the carboxyl group (-COO^{-}), amino group (-NH_{2}), hydrogen atom (H) and a residual R-group. On the structure of the residual R-group the name of the amino acid depends. Like if R is hydrogen (H) the amino acid is alanine; If R- group is a phenyl group i.e. -C_{6}H_{5}, the compound is called phenyl alanine. The structure of the general amino acid skeleton can be shown as-

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Aliyah marks a line on her driveway with a piece of chalk and another line 50ft away Then she stands with both feet at the line
Mariulka [41]

Answer:

Speed

Explanation:

Aliyah must have been trying to find her speed.

The speed is a measure of how fast an object or a body is and it is calculated by finding the ratio of distance with time. Mathematically,

  speed = \frac{distance}{time} with a unit of m/s.

<em>Hence, with the distance measured on the ground and Aliyah trying to find the time it will take her to cover the distance while running, she must have been trying to find how fast she can run, that is, speed. </em>

3 0
3 years ago
Complete the equation for the dissociation of Na2CO3(aq).Omit water from the equation because it is understood to be present.
ozzi

Answer:

Na2CO3 <==> 2Na^+ + CO3^2-

Explanation:

6 0
2 years ago
254950m to millimeter
Arte-miy333 [17]
254950000 millimeters
7 0
3 years ago
Is boron an element a compound a heterogeneous mixture or a homogeneous mixture?
liberstina [14]
The answer is heterogeneous mixture<span> because the </span>blood<span> cells are physically separate from the </span>blood<span> plasma.</span>
3 0
3 years ago
What is that the theoretical yield of aluminum oxide I if 3.20 mol of aluminum metal is exposed to 2.70 mole of oxygen
photoshop1234 [79]

Answer:

163.2g

Explanation:

First let us generate a balanced equation for the reaction. This is shown below:

4Al + 3O2 —> 2Al2O3

From the question given, were were told that 3.2moles of aluminium was exposed to 2.7moles of oxygen. Judging by this, oxygen is excess.

From the equation,

4moles of Al produced 2moles of Al2O3.

Therefore, 3.2moles of Al will produce = (3.2x2)/4 = 1.6mol of Al2O3.

Now, let us covert 1.6mol of Al2O3 to obtain the theoretical yield. This is illustrated below:

Mole of Al2O3 = 1.6mole

Molar Mass of Al2O3 = (27x2) + (16x3) = 54 + 48 =102g/mol

Mass of Al2O3 =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass of Al2O3 = 1.6 x 102 = 163.2g

Therefore the theoretical of Al2O3 is 163.2g

8 0
3 years ago
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