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tresset_1 [31]
3 years ago
9

A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. it suddenly collides directly with a stationary seal of m

ass 200 kg. the seal grabs onto the whale and holds fast. what is the momentum of these two sea creatures just after their collision? you can neglect any drag effects of the water during the collision
Physics
2 answers:
IrinaVladis [17]3 years ago
5 0

Answer:

Pf = 6000 kg*m/s

Explanation:

Using the conservation of the linear momentum:

P_i = P_f

Also:

P_i=M_bV_b

P_f = (M_b+M_s)V_s

Replacing:

M_bV_b = (M_b+M_s)V_s

where M_b is the mass of the whale, V_b is the velocity of te whale, M_s is the mass of the seal and V_s is the velocity of both after the collition.

so:

(1000 kg)(6 m/s) = (1000 kg+ 200kg)V_s

Solving for V_s:

V_s = 5 m/s

Finally for find the momentum we will use the next equation:

P_f = (M_b+M_s)V_s

Pf = (1000+200)(5 m/s)

Pf = 6000 kg*m/s

Alternative:

we know that the linear momentum is conserved so, we only have to know the initial momentum for have the answer:

P_i=M_bV_b

Pi = (1000)(6 m/s)

Pi = 6000 Kg*m/s

Sphinxa [80]3 years ago
3 0

M = mass of the whale = 1000 kg

m = mass of the seal = 200 kg

V = initial velocity of whale before collision with the seal = 6.0 m/s

v = initial velocity of the seal before collision with the whale = 0 m/s

V' = final velocity of two sea creatures after collision = ?

Using conservation of momentum

M V + m v = (M + m) V'

inserting the above values in the equation

(1000 kg) (6.0 m/s) + (200 kg) (0 m/s ) = (1000 kg + 200 kg) V'

6000 kgm/s + 0 kgm/s = (1200 kg) V'

V' = (6000 kgm/s ) /(1200 kg)

V' = 5 m/s

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