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luda_lava [24]
2 years ago
12

In Chile, the deepest earthquake occurred at 61.7°W longitude at a depth of 540 km. If the rocks at the focus began subducting 1

0 million years ago and are now 1000 km from their original position, what is the average rate of subduction in cm/yr?
Chemistry
1 answer:
victus00 [196]2 years ago
5 0

The correct answer is - 1 cm/yr.

Alongside the western coast of South America, the Nazca plate and the South American plate are in a collision for several million years now, with the Nazca plate being the one that is subducting in this convergent plate boundary.

If the Nazca plate's focus has moved 1,000 km in the last 10 million years, than in order to get to the annual movement of the subduction we need to convert the km into cm first:

1 km = 10,000 cm

1,000 x 10,000 = 10,000,000

1,000 km = 10,000,000 cm

Than we need to divide the number of cm with the number of years:

10,000,000 / 10,000,000 = 1

And we get the result of 1 cm/yr.

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When 8.70 kJ of thermal energy is added to 2.50 mol of liquid methanol, it vaporizes. Determine the heat of vaporization in kJ/m
andreev551 [17]

Answer:

The heat of vaporization in kJ/mol of methanol

= 3.48 kJ/mole

Explanation:

Here,the heat of vaporization in kJ/mol is asked to calculate.<em><u>This means it is asked to calculate heat required for 1 mole of methanol.</u></em> Since the substance<em> vaporizes </em>, so this is called <u>heat of vaporization.</u>

Divide the thermal energy with the number of moles .

This is simple mathematics :

If 2.50 mol of liquid require = 8.70 kJ of energy

Then, 1 mole will need =

\frac{8.70}{2.50}

= 3.48 kJ/mole

<em><u>Follow the units :</u></em>

The heat of vaporization in kJ/mol of methanol is asked.

Heat\ of\ Vaporization=\frac{Thermal\ energy}{Moles}

=\frac{kJ}{mole}

Unit = kJ /Mole

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3 years ago
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