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3 years ago

What is role of skin in balancing body temperature during strenous excervise

Physics

1 answer:

trapecia [35]3 years ago

3 0

Answer:

The skin releases sweat

Explanation:

The body temperature is necessary to maintain homeostasis. Skin controls body temperature by sweating when it is too heated.

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A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the

Harman [31]

Answer:

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

F1 = T- 46, 674.656 gm/s²

Explanation:

Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

F1 = T- 46, 674.656 gm/s²

4 0

2 years ago

When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

Natali5045456 [20]

Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And $\theta$ be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration $gsin\theta$

Rob equation of motion can be modeled as s = a_Rt_R^2/2 = a300^2/2 = 45000a[/tex]

Jim equation of motion is $s = a_Jt_J^2/2 = (3a/4)t_J^2/2 = 3at_J^2/8$

As both of them cover the same distance

$45000a = 3at_J^2/8$

$t_J^2 = 45000*8/3 = 120000$

$t_J = \sqrt{120000} = 346.4 s$

So Jim should start 346.4 – 300 = 46.4 seconds earlier than Rob in other to reach the end at the same time

7 0

3 years ago

A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr

IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity $g=9.8m/sec^2$

Specific gravity of oil = 0.600

So density of oil $\rho =0.6\times 1000=600kg/m^3$

We know that absolute pressure is given by $P=P_0+\rho gh$ , here $P_0=1.01\times 10^5Pa$

So absolute pressure will be equal to $P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa$

So absolute pressure of the oil will be 102822.8 Pa

6 0

3 years ago

Raising 100 grams of water from 40 to 60 °C (the specific heat capacity of water is 1

ANTONII [103]

C. 2000 calories.

Explanation/calculation:

Specific heat capacity = calories / mass * (final temperature - initial temperature)

1 = calories / 100 * (60 - 40)
1 = calories / 100 * 20
1 * (100 * 20) = calories
1 * 2000 = calories
2000 = calories

5 0

3 years ago

Read 2 more answers

Is hydrogen balloon element mixture or compound

andrezito [222]

Answer:

compound

Explanation:

5 0

2 years ago