Answer:
A point is a 0-D object, infinitely small.
Explanation:
<u>Answer:</u> The boiling point of water in Tibet is 69.9°C
<u>Explanation:</u>
To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:
![\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7BP_2%7D%7BP_1%7D%29%3D%5Cfrac%7B%5CDelta%20H%7D%7BR%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg (Conversion factor: 1 atm = 760 mmHg)
= final pressure = 240. mmHg
= Heat of vaporization = 40.7 kJ/mol = 40700 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314 J/mol K
= initial temperature or normal boiling point of water = ![100^oC=[100+273]K=373K](https://tex.z-dn.net/?f=100%5EoC%3D%5B100%2B273%5DK%3D373K)
= final temperature = ?
Putting values in above equation, we get:
![\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7B240%7D%7B760%7D%29%3D%5Cfrac%7B40700J%2Fmol%7D%7B8.314J%2Fmol.K%7D%5B%5Cfrac%7B1%7D%7B373%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D%5C%5C%5C%5C-1.153%3D4895.36%5B%5Cfrac%7BT_2-373%7D%7B373T_2%7D%5D%5C%5C%5C%5CT_2%3D342.9K)
Converting the temperature from kelvins to degree Celsius, by using the conversion factor:
Hence, the boiling point of water in Tibet is 69.9°C
HI
I found a link that will direct you to the answer of this questions
<span>http://click.dji.com/ANbvbbP7bwUWtSACp6U_?pm=link&as=0004</span>
Elemental analysis of a compound containing carbon, hydrogen, nitrogen, and oxygen gave the following mass percentages for each element: C: 42.36% H: 3.555% N: 16.47% O: 37.62% The <em>molar mass</em> of the compound is Molecular formula = C6H14N2O2 Consider the total mass of the compound =100g Then mass of carbon = 49.30 g Mass of hydrogen = 9.653 g Mass of nitrogen = 19.16 g Mass of oxygen = 21.89 g Molar mass of carbon = 12.0 g/mol
<h3>What is
molar mass ?</h3>
In chemistry, the molar mass of a chemical compound is determined by dividing its mass by the molecular weight of the component that makes up the sample. The molar mass of a substance is a bulk attribute rather than a molecular one. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes. A terrestrial average and a function of the relative abundance of the isotopes of the constituent atoms on Earth, the molar mass is most frequently calculated using the standard atomic weights. For converting between a substance's mass and amount in bulk amounts, the molar mass is the proper unit.
To learn more about molar mass from the given link:
brainly.com/question/22503632
#SPJ4
<span>First, divide the mass of N2O by it's molar mass of 46 g/mol to determine the number of moles of N2O, then multiply that number by two since there are two moles of N in each mole of the compound N2O. This results in a final answer of 9.78X10^-3 moles of N in 0.225g of N2O.</span>
