To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:
Mass Moles
K 52.10 52.10/39.10 = 1.33 1.33/1.32 ≈ 1
C 15.8 15.8/12 = 1.32 1.32/1.32 ≈ 1
O 32.1 32.1 / 16 = 2.01 2.01/1.32 ≈ 1.5
The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.
Protons are one of the fully stable parts of matter
I'm pretty sure its momentum
Answer:
Answer in explanation
Explanation:
A. This is wrong. The reactants are on the left side of the yields arrow
B. This is wrong. They can only be at one side at a time. They cannot be on both sides at the same time.
C. The products are on the right side of the yields arrow and not at the left side
D. This is correct. The reactants are on the left side of the yields arrow.
E. This is correct. We can have varying numbers of the number of atoms on both side of the yields arrow. The numbers may differ until we decide to balance the equation
Answer:
The atomic weight of an element represents the ratio of the average mass of atoms of a chemical element.
