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Elena-2011 [213]
3 years ago
9

How is stoichiometry used to calculate energy released when a mass of liquid freezes?

Chemistry
2 answers:
nataly862011 [7]3 years ago
8 0

Answer:

The answer is B via a p e x.

Grams liquid x mol/g x delta Hfusion

kati45 [8]3 years ago
6 0

Answer:

D. Grams liquid x mol/g x delta Hf​reezing

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to reason that the stoichiometry used to calculate energy released when a mass of liquid freezes, involves the grams of the liquid, the molar mass of the liquid, as given in all the group choices, and the enthalpy of freezing because that is the process whereby a liquid goes solid.

In such a way, we infer that the correct factor would be D. Grams liquid x mol/g x delta Hf​reezing which sometimes is the negative of the enthalpy of fusion as they are contrary processes.

Regards!

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The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for eithe
Tasya [4]

Answer:

The answer is "K_1 < K_2"

Explanation:

In the given question, the value of the K=Ae^{-\frac{Ea}{RT}} and the T_1is the rate value which is the constant that is  K_2>K_1. As per the temperature value when its increase rate is constantly increasing. E_a is activation energy it is not dependent on the temperature that why the answer is K_1 < K_2.

8 0
3 years ago
Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AlX. Element X is a diatomic gas
Sergio039 [100]

Answer:

It's nitrogen

Explanation:

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5 0
2 years ago
Coffee shops sell paper coffee<br> cups with cardboard sleeves<br> for customer safety. Why?
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4 0
2 years ago
How would you properly measure the mass of a liquid
MArishka [77]
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4 0
3 years ago
Do you expect a strong chemical bond to have a higher or lower frequency than a weak bond?
Llana [10]

Answer:

Higher frequency  

Explanation:

We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.

According to Hooke's Law, the stretching frequency f is

f = \dfrac{1}{2 \pi}\sqrt{ \dfrac {k}{\mu}}

where µ is the reduced mass of the system

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The strength of the bond is analogous to k, the force constant of the spring. Then,

f \propto \sqrt{k}

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6 0
3 years ago
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