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2 years ago

How is stoichiometry used to calculate energy released when a mass of liquid freezes?

Chemistry

2 answers:

nataly862011 [7]2 years ago

8 0

Answer:

The answer is B via a p e x.

Grams liquid x mol/g x delta Hfusion

kati45 [8]2 years ago

6 0

Answer:

D. Grams liquid x mol/g x delta Hfreezing

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to reason that the stoichiometry used to calculate energy released when a mass of liquid freezes, involves the grams of the liquid, the molar mass of the liquid, as given in all the group choices, and the enthalpy of freezing because that is the process whereby a liquid goes solid.

In such a way, we infer that the correct factor would be D. Grams liquid x mol/g x delta Hfreezing which sometimes is the negative of the enthalpy of fusion as they are contrary processes.

Regards!

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Explanation:

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$Molarity=\frac{n\times 1000}{V_s}$

where,

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To calculate the moles, we use the equation:

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$2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ba(OH)_2$

We are given:

$n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL$

Putting values in above equation, we get:

$1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M$

Thus the concentration of the acid is 1.36 M

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