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jeyben [28]
3 years ago
12

A bicyclist steadily speeds up from rest to 9.00m/s during a 7.20s time interval. Determine all unknowns and answer the followin

g questions. What is the magnitude of the bicyclist's acceleration? unit How far did the bicyclist travel during this time? unit​
Physics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

First, let us make some simplifications in notation. Taking the initial time to be zero, as if time is measured with a stopwatch, is a great simplification. Since elapsed time is

Δ

t

=

t

f

−

t

0

, taking

t

0

=

0

 means that

Δ

t

=

t

f

, the final time on the stopwatch. When initial time is taken to be zero, we use the subscript 0 to denote initial values of position and velocity. That is,

x

0

is the initial position and

v

0

is the initial velocity. We put no subscripts on the final values. That is,

t

is the final time,

x

is the final position, and

v

is the final velocity. This gives a simpler expression for elapsed time—now,

Δ

t

=

t

. It also simplifies the expression for displacement, which is now

Δ

x

=

x

−

x

0

. Also, it simplifies the expression for change in velocity, which is now

Δ

v

=

v

−

v

0

. To summarize, using the simplified notation, with the initial time taken to be zero,

Δ

t

=

t

Δ

x

=

x

−

x

0

Δ

v

=

v

−

v

0

 

}

Explanation:

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¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula
Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

7 0
3 years ago
What relationship does mass have with inertia
stira [4]
Inertia is a term that qualitatively describes the ability of a substance to resist changes in its state of motion, while mass gives a quantitative value for inertia
7 0
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A 64.8 kg astronaut is on a space walk when the tether line to the shuttle breaks. The astronaut is able to throw a 11.0 kg oxyg
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3 years ago
What is the kinetic energy of a bike with a mass of 24 kg traveling at 3 m/s?
erastovalidia [21]

Answer:

KE = 1/2mv^2

KE = 1/2(24)(3^2)

KE = 12(9)

KE = 108 J

Let me know if this helps!

5 0
3 years ago
What's the equivalent resistance to the resistances shown?<br><br>A) 5<br>B) 6<br>C) 2<br>D) 3
PIT_PIT [208]
From A to B its 5 ohm.
above shown 6 and 12 ohm resistors are in parallel to short circuit hence their equivalent resistance is zero.
(Current doesnt flow through a resisstor if there is a Short circuit alternate.
6 0
3 years ago
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