Complete Question:
One simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.5 m/s in 2.24 s, what will be his total time?
Answer:
total time = 6.24 s
Explanation:
Using the equation of motion:
v = u + at
initial speed, u = 0 m/s
v = 11.5 m/s
t = 2.24 s
11.5 = 0 + 2.24a
a = 11.5/2.24
a = 5.13 m/s²
For the total time spent by the sprinter:
s = ut + 0.5at²
100 = 0.5 * 5.13 * t²
t² = 100/2.567
t² = 38.957
t = √38.957
t = 6.24 s
When a candle is burning and
wind is blowing it on one side of the flame, which causes the flame to bend
towards the wind is an example of Bernoulli’s principle. The principle explain
that the higher the speed,
the lower the pressure becomes. When you blow against one side of the flame, you are creating
an area of low pressure. The relatively high-pressure air on the other side of
the candle will rush over to fill the area of low pressure that causes the flame to be
pushed in the direction of the blowing.
Answer:
1.3 × 10⁸ e⁻
Explanation:
When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:
20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻
1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:
2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure difference of the first bubble is 
The pressure difference of the second bubble is 
The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger
Explanation:
From the question we are told that
The radius of the first bubble is 
The radius of the second bubble is 
The surface tension of the soap solution is 
Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as
Now the pressure difference for the first bubble is mathematically evaluated as
substituting values
Now the pressure difference for the second bubble is mathematically evaluated as
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