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Sedbober [7]
3 years ago
7

A square-based shipping crate is being designed that must contain a volume of 16 ft3 . The material that is used for the base an

d the lid costs 3 dollars/ft2 , while the material used for the sides costs 2 dollars/ft2 . What are the most cost-effective dimensions of such a crate?
Physics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

Explanation:

Given

volume V=16 ft^3

Suppose base is square with side L

height of crate is h

Volume V=L^2\times h

16=L^2\times h

Cost of top and bottom area c_1=3L^2

Cost of Side area c_2=4Lh\times 2=8Lh=8L\times \frac{16}{L^2}=\frac{128}{L}

Total Cost C=c_1+c_2

Total Cost C=3L^2+\frac{128}{L}

Differentiate C w.r.t Length

\frac{dC}{dL}=6L-\frac{128}{L^2}

L^3=\frac{128}{6}

L=2.75 ft

h=\frac{16}{2.75^2}=11.46 ft

Dimensions are L\times L\times h=2.75\times 2.75\times 11.46    

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