Answer: D. There is a lot of light pollution on earth
Explanation: The light pollution on Earth has nothing to do with the stars in the sky
Answer:
it states that energy can neither be created or destroyed
A 1.5 kg bird is gliding at a height of 12 m with a speed of 3.8m/s. The kinetic energy of the bird is 10.83 joules.
Explanation:
Kinetic energy can be defined as,The kinetic energy (KE) of an object is the energy that the object possesses due to its motion.
The Kinetic energy can be calculated by using formula,
Kinetic Energy: KE = 1/2 (mv 2)
Where, m = Mass, v = Velocity.
Here in this case the bird mass is 1.5kg and is gliding with velocity 3.8m/s
hence, KE= 1/2*(1.5)×(3.8)^2
=0.5×1.5×3.8×3.8
=10.83Joules
The impact would be great it would possibly freeze the work or melt the polar ice caps and flood the world to were we would invent technology light years away.
Answer:
8.8 m and 52.5 m
Explanation:
The vertical component and horizontal component of water velocity leaving the hose are
![v_v = vsin(\alpha) = 25sin(53^0) = 25*0.8 = 19.97 m/s](https://tex.z-dn.net/?f=v_v%20%3D%20vsin%28%5Calpha%29%20%3D%2025sin%2853%5E0%29%20%3D%2025%2A0.8%20%3D%2019.97%20m%2Fs)
![v_h = vcos(\alpha) = 25cos(53^0) = 25*0.6 = 15 m/s](https://tex.z-dn.net/?f=v_h%20%3D%20vcos%28%5Calpha%29%20%3D%2025cos%2853%5E0%29%20%3D%2025%2A0.6%20%3D%2015%20m%2Fs)
Neglect air resistance, vertically speaking, gravitational acceleration g = -9.8m/s2 is the only thing that affects water motion. We can find the time t that it takes to reach the blaze 10m above ground level
![s = v_vt + gt^2/2](https://tex.z-dn.net/?f=%20s%20%3D%20v_vt%20%2B%20gt%5E2%2F2)
![10 = 19.97t - 9.8t^2/2](https://tex.z-dn.net/?f=10%20%3D%2019.97t%20-%209.8t%5E2%2F2)
![4.9t^2 - 19.97t + 10 = 0](https://tex.z-dn.net/?f=4.9t%5E2%20-%2019.97t%20%2B%2010%20%3D%200)
t = 3.49 or t = 0.58
We have 2 solutions for t, one is 0.58 when it first reach the blaze during the 1st shoot up, the other is 3.49s when it falls down
t is also the times it takes to travel across horizontally. We can use this to compute the horizontal distance between the fire-fighters and the building
![s_1 = v_ht_1 = 15*0.58 = 8.8 m](https://tex.z-dn.net/?f=s_1%20%3D%20v_ht_1%20%3D%2015%2A0.58%20%3D%208.8%20m)
![s_2 = v_ht_2 = 15*3.49 = 52.5m](https://tex.z-dn.net/?f=s_2%20%3D%20v_ht_2%20%3D%2015%2A3.49%20%3D%2052.5m)