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vladimir2022 [97]
3 years ago
13

I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!

Physics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

h

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law[1] of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force.[2] The law was first discovered in 1785 by French physicist Charles-Augustin de Coulomb, hence the name. Coulomb's law was essential to the development of the theory of electromagnetism, maybe even its starting point,[1] as it made it possible to discuss the quantity of electric charge in a meaningful way.[3]

The law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them,[4]

{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}

Here, ke is Coulomb's constant (ke ≈ 8.988×109 N⋅m2⋅C−2),[1] q1 and q2 are the signed magnitudes of the charges, and the scalar r is the distance between the charges.

The force is along the straight line joining the two charges. If the charges have the same sign, the electrostatic force between them is repulsive; if they have different signs, the force between them is attractive.

Being an inverse-square law, the law is analogous to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.[2] Coulomb's law can be used to derive Gauss's law, and vice versa. In the case of a single stationary point charge, the two laws are equivalent, expressing the same physical law in different ways.[5] The law has been tested extensively, and observations have upheld the law on the scale from 10−16 m to 108 m.[5]

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Por una espira de 0.5 m2 de área circula una corriente de 5 A. Calcula la densi- dad de flujo magnético B considerando que la es
Sloan [31]

Answer:

\beta=B=8.05\mu T

Explanation:

The density of the magnetic flux is given by the following formula:

\beta=\frac{\Phi_B}{A}=\frac{ABcos\theta}{A}=Bcos\theta

The normal vector A and the vector of the magnitude of the magnetic field are perpendicular, then, the angle is zero:

The magnitude of the magnetic field is calculated by using the formula for B at a distance of x to a point in the plane of the loop:

B=\frac{\mu_oIR^2}{2(x^2+R^2)^{3/2}}

For x = 0 you have:

B=\frac{\mu_oIR^2}{2R^3}=\frac{\mu_oI}{2R}

R is the radius of the circular loop and its values is:

R=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{0.5m^2}{\pi}}=0.39m

Then, you replace in the equation for B with mu_o = 4\pi*10^-7 T/A:

B=\frac{(4\pi*10^{-7}T/A)(5A)}{2(0.39m)}=8.05*10^{-6}T=8.05\mu T

and the density of the magnetic flux is

\beta=B=8.05\mu T

4 0
4 years ago
6)
tiny-mole [99]

Answer: 14.5 N

Explanation:   NEED SCRATCH PAPER: A flower pot weighing 42.0 N (newtons) is hung above a window by three ropes, each making an angle of 15.0 degrees with the vertical. What is the tension in each rope supporting the flower pot?

✓ 14.5 N

found it on the internet?

5 0
3 years ago
Compare the de Broglie wavelength of an electron moving at 1.30×107 miles per hour (5.81×106 m/s) to that of a bullet moving at
lesya [120]

Answer:

electron  λ = 12.5 nm , bullet  λ = 1.11 10⁻³³ m  and golf ball  λ = 4.7 10⁻³⁴ m

Explanation:

The Broglie wave duality principle states that all matter has wave and particle properties, it is expressed by the equation

      p = h / λ

Where lam is called broglie wavelength

Let's use the definition of momentum

       p = mv

Let's calculate the wavelengths

-Electron

     mv = h /λ

     λ = h / mv

     λ = 6.63 10⁻³⁴ / (9.1 10⁻³¹ 5.81 10⁶)  

     λ = 1.25 10⁻¹⁰ m

     λ = 12.5 nm

This is the X-ray region

-bullet

     λ = 6.63 10⁻³⁴ / (1.90 10⁻³  313)

     λ = 1.11 10⁻³³ m

It is too small, only particle characteristics are observed

-Golf ball

     λ = 6.63 10⁻³⁴ / (4.50 10⁻² 31.3)

    λ = 4.7 10⁻³⁴ m

Too small, only particle characteristics are visible

7 0
3 years ago
A body is under the action of two forces 7N and 10N. Find the resultant of the two forces if the forces are parallel and act in
snow_lady [41]

Answer:K;O9KGVB  

Explanation:

3 0
3 years ago
A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

7 0
3 years ago
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