2-ciclopropilpropano

How many calories is required to change the temperature of 2.18g of water from 15.3°C to 69.5°C. The specific heat of liquid wat

lozanna [386]

The number of calories that are required to change the temperature of 2.18 g of water from 15.3 c to 69.5 c is 118.16 cal

calculation

Heat in calories = MCΔ T where,

M(mass)= 2.18 g
C(specific heat capacity)= 1.00 cal/g/c
ΔT( change in temperature)= 69.5- 15.3 =54.2 c

heat is therefore= 2.18 g x 1.00 cal/g/c x 54.2 c=118.16 cal

7 0

3 years ago

Read 2 more answers

12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?

Kaylis [27]

Answer:

$115.625^{\circ}\text{F}$

Explanation:

$m_1$ = First mass of water = 12 oz

$m_2$ = Second mass of water = 20 oz

$\Delta T_1$ = Temperature difference of the solution with respect to the first mass of water = $(T-75)^{\circ}\text{F}$

$\Delta T_2$ = Temperature difference of the solution with respect to the second mass of water = $(T-75)^{\circ}\text{F}$

c = Specific heat of water

As heat gain and loss in the system is equal we have

$m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}$

The final temperature of the solution is $115.625^{\circ}\text{F}$ .

3 0

2 years ago

Step 2: measure the area of the top of the syringe

Elena L [17]

I am unsure if this is correct, but this might be the whole section:

The top of the syringe is a circle. You need to compute its area for use in later computations of pressure values. Start by using a ruler to measure the diameter. Estimate to the nearest 0.01 cm. Answer: 3.60 cm
Divide by two to find the radius. Maintain significant figures. Answer: 1.80 cm
Substitute the radius into the formula A = πr² to find the area of the top of the syringe. Maintain significant figures. Answer: 10.2 cm²

6 0

2 years ago

Consider the equation:

Dmitry [639]

Answer:1. $Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. The rate constant (k) for the reaction is $3.50M^\frac{-1}{2}s^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$rate=k[CHCl_3]^x[Cl_2]^y$