Answer:
333K
Explanation:
Answer is actually 333.15, but to round it off, is 333
The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound. Shown in attachment are the two Lewis structures of the compound with molecular formula C4H10. The two structures are the isomers of each other.
Butane is an alkane represented by C4H10. All the bonds in this situation are single bonds because this substance is an alkane. Two shared electrons are present in every bond.
Each carbon atom requires 8 electrons around it in order to follow the Octet Rule. The octet rule was completed by the hydrogen bonds, eliminating the need for the electron dots.
Straight-chained butane is the first structure. The y-chained isobutane is the second structure.
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Answer:
Paraffin > Heptadecane > Hexane > 2,2-dimethylbutane > Propane
Explanation:
It must first be establish that all the molecules listed in the question are alkanes. For alkanes, the intermolecular forces between the molecules of alkanes increases with increasing molecular weight. This is as a result of increase in the surface area of the molecule. Increase in surface area implies a greater degree of dispersion forces.
This is the reason why high boiling points are observed for high molecular weight alkanes.
-A bromine with an incomplete octet and a positive charge.
-A bromine with an incomplete octet and a positive charge and an oxygen with ten valence electrons and two charges.
-A compound with the bond between a bromine and an oxygen with three bonds.