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2 years ago

Will calcium metal react with chromium (III) chloride? Explain your answer

1 answer:

5 0

Calcium metal with chromium(III) chloride would react. Calcium metal is more reactive than chromium metal; therefore, putting calcium metal in chromium chloride would create a reaction, where as putting chromium metal in calcium chloride would not form any reaction.

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Which type of bond is found between atoms of solid cobalt?

Vsevolod [243]

The answer is (3) metallic. Cobalt is a transition metal, so it can't be covalent bonds, which bond non-metals, therefore eliminating choice 1 and 2. Ionic bonds are between metals and non metals, but solid cobalt does not have a non metal, eliminating choice 4 as well. Metallic bonds are bonds between metals, therefore the answer is (3) metallic.

3 0

3 years ago

Read 2 more answers

Which answer below correctly identifies the type of change and the explanation for the boiling of water?

Lynna [10]

physical change because even though gas formation was observed, the water was undergoing a state change, which means that its original properties are preserved

Explanation:

The boiling of water is a physical change because the original properties of the water is preserved.

A physical change is the one that alters the physical properties of matter.
This kind of change is easily reversible as the water can be cooled back.
No new kinds of matter is produced in this kind of change .
The molecules of the matter still retains their property after.

During the boiling of water, intermolecular bonds called hydrogen bonds between the water molecules are broken. This makes the individual molecules free.

Learn more:

Hydrogen bonds brainly.com/question/10602513

#learnwithBrainly

7 0

2 years ago

What are electron configurations?

sweet-ann [11.9K]

electron configuration is the arrangement of electrons in an atom, molecule, or other physical structure (e.g., a crystal).

3 0

2 years ago

When explaining about structural classifications to a group of students, the instructor discusses the peptides and proteins. The

stepladder [879]

Answer:

There are approximately 200 amino acids.

Explanation:

Proteins are usually larger than peptides. In addition, proteins contains amino acids which are about 50 and more than while the amino acids in peptides are just between 2 and 50. On the other hand, growth hormone which is also known as somatotropin is a type of peptide cell regeneration, growth, and reproduction. The number of amino acids in the growth hormones are approximately 200.

5 0

2 years ago

State whether the sign of the entropy change expected for each of the following processes will be positive or negative, and expl

Strike441 [17]

Answer:

a) ΔS is negative

b) ΔS is positive

c) ΔS is positive

d) ΔS is negative

Explanation:

Entropy (S) is a thermodynamic parameter which measures the randomness or the disorder in a system. Greater the disorder more positive will be the value of entropy.

The extent of disorder increases as substances transition from the solid to the gaseous state. i.e.

S(solid) < S(liquid) < S(gas)

The entropy change for a given reaction is:

$\Delta S = S(products)-S(reactants)----(1)$

a) $PCl3(l) + Cl2(g) \rightarrow PCl5(s)$

Here the reactants are in the liquid and gas phase which have higher entropy than the product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

b) $2HgO(s) \rightarrow 2Hg(l) + O2(g)$

Here the products are in the liquid and gas phase which have higher entropy than the reactant which is in the solid phase i.e. lower entropy.

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

c) $H2(g) \rightarrow 2H(g)$

Here the products and reactants are in the gas phase. However the number of moles of products is greater than the reactants

Since S(product) > S(reactant), based on equation 1, ΔS will be positive.

d) $U(s) + 3F2(g) \rightarrow UF6(s)$

Here one of the reactants is in the gas phase which corresponds to a more positive entropy compared to the product which is in the solid phase i.e. lower entropy.

Since S(product) < S(reactant), based on equation 1, ΔS will be negative.

8 0

2 years ago