Answer: 1766.667 Ω = 1.767kΩ
Explanation:
V=iR
where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).
3mA = 0.003 A
Rearranging the equation, we get
R=V/i
Now we are solving for resistance. Plug in 0.003 A and 5.3 V.
R = 5.3 / 0.003
= 1766.6667 Ω
= 1.7666667 kΩ
The 6s are repeating so round off to whichever value you need for exactness.
Answer:
peak-hour volume = 1890 veh/h
Explanation:
<u>Determine the peak-hour Volume </u>
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
<u>Back to equation 1 </u>
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
Answer:
ere el merjor 5iyer
Explanation:
yyhh espero ayuder 8 mucho 666
Answer:
Baseband is a signal that has a near zero frequency range. In telecommunication and signal processing, baseband are transmitted without modulation.
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