Answer:
2.44 mV
Explanation:
This question has to be one of analog quantization size questions and as such, we use the formula
Q = (V₂ - V₁) / 2^n
Where
n = 12
V₂ = higher voltage, 5 V
V₁ = lower voltage, -5 V
Q = is the change in voltage were looking for
On applying the formula and substitutiting the values we have
Q = (5 - -5) / 2^12
Q = 10 / 4096
Q = 0.00244 V, or we say, 2.44 mV
Answer:
load = 156 lb/ft
Explanation:
given data
interior wall of a building = 2×4 wood studs
plastered = 1 side
wall height = 13 ft
solution
we get here load so first we get wood stud load and that is
we know here from ASCE-7 norm
dead load of 2 x 4 wood studs with 1 side plaster = 12 psf
and we have given height 13 ft
so load will be = 12 psf × 13 ft
load = 156 lb/ft
Answer:
investor claim is acceptable
Explanation:
given data
Win = 0.25 kW
Qc = 3000 J/s = 3kW
Th = 293 K
Tc = 270 K
solution
we get here coefficient of performance of cycle is
coefficient of performance =
..................1
put here value and we get
coefficient of performance =
coefficient of performance = 1.2
and
coefficient of performance of ideal refrigeration is
coefficient of performance =
..................2
coefficient of performance =
coefficient of performance = 11.74
and
we can see here that coefficient of performance of ideal refrigeration is is more than real cycle coefficient of performance
so investor claim is acceptable