Answer:
option C
Explanation:
Let mass of the bullet be m and velocity be v
mass of gun be M and bullet be V
now,
using conservation of momentum for gun 1
(M+m) V' = 2 mv + 3 MV
V' = 0
3 M V = - 2 mv
momentum of gun 1 =- 2 mv---------(1)
now for gun 2
(M+m) V' = mv + MV
V' = 0
M V = - mv
momentum of gun 1 = -mv-----------(2)
dividing equation (1) by (2)


the correct answer is option C
Answer:
v_f = 10.38 m / s
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
note that the two quantities are scalars
Work is defined by the relation
W = F. Δx
the bold are vectors. The displacement is
Δx = r_f -r₀
Δx = (11.6 i - 2j) - (4.4 i + 5j)
Δx = (7.2 i - 7 j) m
W = (4 i - 9j). (7.2 i - 7 j)
remember that the dot product
i.i = j.j = 1
i.j = 0
W = 4 7.2 + 9 7
W = 91.8 J
the initial kinetic energy is
Ko = ½ m vo²
Ko = ½ 2.0 4.0²
Ko = 16 J
we substitute in the initial equation
W = K_f - K₀
K_f = W + K₀
½ m v_f² = W + K₀
v_f² = 2 / m (W + K₀)
v_f² = 2/2 (91.8 + 16)
v_f = √107.8
v_f = 10.38 m / s
Answer:
That is an example of Radiational transfer
Explanation:
Radiation is a direct transfer of exposer
Answer:
0.96cm
Explanation:
Given parameters:
Weight of person = 645N
Pressure of the heel = 9000000PA
Unknown
Diameter of the circular base = ?
Solution
Pressure is the force per unit area of a body.
Pressure = 
To solve this problem, find the unknown area of the circle;
Pressure x Area = Force
Area = 
Area =
= 7.17 x 10⁻⁵m²
Note: 1Pa = 1Nm⁻²
Now;
Area of a circle = π r²
r = 
Area = π x 
d is the diameter
d² = 4 x Area x (1/π)
d² = 4 x 7.17 x 10⁻⁵ x (1/3.14) = 9.13 x 10⁻⁵
d = 0.0096m
To cm;
100cm = 1m
0.0096m; 0.0096 x 100= 0.96cm