The question for this problem would be the minimum headphone delay, in ms, that will cancel this noise.
The 200 Hz. period = (1/200) = 0.005 sec. It will need to be delayed by 1/2, so 0.005/2, that is = 0.0025 sec. So converting sec to ms, will give us the delay of:Delay = 2.5 ms.
If they both are moving with the same speed and direction
i.e. covering the same distance in the same time interval in the same direction
Answer:
The unit of speed is m/s.
The force needed to keep the space shuttle moving at constant speed is 0.
The given parameters;
- <em>weight of the space shuttle, F = 750,000 N</em>
- <em>constant speed of the space shuttle, v = 28,000 km/h</em>
The mass of the space shuttle is calculated as follows;

The force needed to keep the space shuttle moving at constant speed is calculated as follows;


where;
a is the acceleration of the space shuttle
At a constant speed, acceleration is zero.
F = 76,530.61 x 0
F = 0
Thus, the force needed to keep the space shuttle moving at constant speed is 0.
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Answer:
F = 351×10³lb
Explanation:
Given the density
ρg = 64.6lb/ft³
Diameter d = 12ft
The tank is horizontally cylindrical. The vertical distance from the top to the bottom of the tank is h = 12ft
The pressure in the tank is
P = ρgh = 64.6 × 12 = 775.2lb/ft²
The force exerted on one end of the tank is therefore F = PA = 775.2 × πd² = 775.2π×12²
F = 351×10³lb.